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Triss [41]
3 years ago
12

What six time twentyone

Mathematics
1 answer:
yarga [219]3 years ago
4 0

126 is the answer you are looking for


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If a 45 degree 45 degree 90 degree triangle has a hypotenuse length of 12 find the leg length
AURORKA [14]

Answer:

<h2>Leg length = 8.5</h2><h2 />

Step-by-step explanation:

let x represent the leg length

if we use the Pythagorean theorem we get:

x² + x² = 12²

then

2x² = 12²

Then

x² = 144/2 = 72

then

x = √(72)

 =8,485281374239

7 0
3 years ago
How do you solve systems of equations using matrices? I need help with the steps please
seraphim [82]
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.

6 0
3 years ago
What is the area of the figure
mel-nik [20]
The entire picture is needed to solve. the bottom of the pic is cut off
6 0
3 years ago
P=-40q+163, what is the relationship between p and q?
Alex Ar [27]
P=-40q+163 

p-163=-40q 

- \dfrac{p-163}{40}=q 

q= - \dfrac{p-163}{40}
4 0
3 years ago
Write the equation of the graph
olchik [2.2K]

Answer:

y = 2.cos(x) - 2

Step-by-step explanation:

1. Shifting cos(x) right or left, top or down, as the graph in the question has the same illustration of  cos(x). Consider

y = a.cos(x) + b

2. find a and b by using two sample points from the graph: (0, 0) and (\pi, -4)

0 = a.cos(0) + b  => a + b = 0\\ -4 = a.cos(\pi) + b => b-a=-4\\\left \{ {{2b=-4} \atop {2a=4}} \right.\\a = 2, b=-2\\

5 0
3 years ago
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