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sergejj [24]
4 years ago
8

Mr. Phillip's investment account lost $50, and gained $200 and then lost $400 . What was the total change in the amount of money

in Mr. Phillips's investment account
Mathematics
2 answers:
lorasvet [3.4K]4 years ago
7 0
He lost 250 hope it helps
Oliga [24]4 years ago
6 0
Answer: He lost 250


Explanation: because of you add 400 and 50 because that what he lost then take 200 of it because he gained that much
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A roll of ribbon was 12 meters long. Diego cut 9 pieces of ribbon that were 0.4 meters each to tie some presents. He then used t
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Answer: 8.4; 14.

Step-by-step explanation:

To find how much ribbon we used to tie presents, we need to multiply 9 and 0.4.

9 x 0.4 = 3.6.

Diego used 3.6 meters of yard to tie some presents. We can subtract that from 12 to find how much ribbon we have left.

12 - 3.6 = 8.4.

We have 8.4 meters of ribbon to make wreaths.

Now we have to find how many wreaths we can make wiht 8.4 meters of ribbon. We know that each wreath needs 0.6, so we should divide 8.4 by 0.6 to find how many wreaths we can make.

8.4 ÷ 0.6 = 14.

Therefore, we can make 14 wreaths with the 8.4 meters of leftover ribbon.

(Part A's answer is 8.4, and Part B's answer is 14)

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3 years ago
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What is the value of log2 18 rounded to the nearest hundredth?
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A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 80% confidence inter
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Answer:

The 80% confidence interval for the mean

(4.6199 , 4.7801)

Step-by-step explanation:

<u>Explanation</u>:-

Assuming that the population standard deviation for the number of energy drinks consumed each week is 1

Given the Population standard deviation 'σ' = 1

The study found that for a sample of 256 teenagers the mean number of energy drinks consumed per week is 4.7

given sample size 'n' = 256

mean of the sample 'x⁻' = 4.7

<u>confidence interval for the mean</u>

The 80% confidence interval for the mean is determined by

(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\alpha }\frac{S.D}{\sqrt{n} } )

the z-score of 80% level of significance = 1.282

(4.7 - 1.282\frac{1}{\sqrt{256} } , 4.7 + 1.282\frac{1}{\sqrt{256} } )

(4.7 - 0.0801 , 4.7 +0.0801)

(4.6199 , 4.7801)

<u>Conclusion</u>:-

The 80% confidence interval for the mean

(4.6199 , 4.7801)

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Answer:

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Step-by-step explanation:

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