The sum of three numbers is 61 the second number is 5 times the first while the third is 2 less than the first find the numbers
1 answer:
Answer:
9 + 45 + 7 = 61
Step-by-step explanation:
a+b+c = 61...eqn 1
b = 5a...eqn 2
c = a - 2...eqn 3
subst for b and c in eqn 1...
=> a+5a+a-2 = 61
=> 7a = 63
=> a = 9
subst for a in eqn 2...
=> b = 5×9 = 45
subst for a in eqn 3...
=> c = 9-2 = 7
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Answer: Step-by-step explanation:
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Answer:
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Answer:
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