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3 years ago

In a basketball game 15 of 20 foul shots that Michelle attempted were successful. What percent of her shots were not successful?

1 answer:

7 0

Work 1:
Successful Percent:
15 divided by 20 equals .75
.75 times 100 is equal to 75
75%
Not successful Percent:
100% minus 75% equals 25%
25%
Work 2:
20 minus 15 equals 5
5 divided by 20 is equal to .25
.25 times 100 is equal to 25
25%

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6 children and 2 adults are going to the circus, children tickets are on sale, half the price of adult tickets totaling $54. How

inna [77]

Answer:

Price of 1 child ticket is $5.4

Price of 1 adult ticket is $10.8

Step-by-step explanation:

Given:-

6 children and 2 adults are going for circus.

Children ticket is half the price of adult ticket.

Total ticketing cost =$54

To find:-

Cost of 1 child ticket=?

Cost of 1 Adult ticket=?

Solution:-

Let price of 1 child ticket be x and price of 1 adult ticket be y,

therefore from the given data we get 2 equations,

$6x+2y=54$ -----------------------------------(1)

$x=\frac{1}{2} y$ --------------------------------(2)

Now, substituting the value of x from equation 2 in equation 1,

$6x+2y=54$

$6(\frac{1}{2} y)+2y=54$

$\frac{6}{2}y+2y=54$

$3y+2y=54$

$5y=54$

$\therefore y=\frac{54}{5}$

$\therefore y =10.8$ ------------------------(3)

Now, substituting the value of y from equation 3 in equation 2,

$x=\frac{1}{2} y$

$\therefore x=\frac{1}{2} \times 10.8$ ------------(from equation 3)

$\therefore x=\frac{10.8}{2}$

$\therefore x=5.4$ ----------------------(4)

As, x is price of 1 child ticket and y is price of 1 adult ticket,

Therefore price of 1 child ticket is $5.4 and price of 1 adult ticket is $10.8

7 0

3 years ago

A painting crew reported that a job is 3/5 completed. What fraction of the job remains to be done?

Debora [2.8K]

Answer:

2/5

Step-by-step explanation:

7 0

3 years ago

2. You plant 48 seeds of a certain flower and 32 of them sprout. Find the

Neko [114]

Answer:

The probability that the next flower seed will sprout is 0.667 or 66.7%

Step-by-step explanation:

Probability

The experimental or empirical probability can be defined as the ratio of the number of times an event occurs to the total number of times the random activity was performed.

It can be calculated as the relative frequency of an event A in a sample space. The question states 32 seeds of a certain flower sprout out of 48 planted seeds. The relative frequency of success is computed as

$\displaystyle P(A)=\frac{32}{48}=\frac{2}{3}=0.667$

Thus, the probability that the next flower seed will sprout is 0.667 or 66.7%

6 0

4 years ago

How to put 24/27 in simplest form

iogann1982 [59]

Answer:

8/9

Step-by-step explanation:

divide both numerator and denominator by 3

therefore u get 8/9

5 0

3 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago