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2 years ago

Julian scored 45 points in a video game. Brenden scored 3 times as many points. How many points did Brenden score?

Mathematics

1 answer:

Zepler [3.9K]2 years ago

3 0

45 times 3 = 135

135 is the answer.

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A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/

xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$

The degrees of freedom for this sample size are:

$df=n-1=25-1=24$

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.318 \cdot 0.016=0.021$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186$

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0

3 years ago

Factor of 42a5b3, 35a3b4, and 42ab4

Scrat [10]

Can u explain it a little more clearly...

4 0

3 years ago

Change 3/2 3.14 to degree measure

EastWind [94]

Answer:

option b

hope ut is help full

6 0

2 years ago

Find the sum

lakkis [162]

Answer:

Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

Step-by-step explanation:

Let

S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator

= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators

= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator

= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand

= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor

= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange

= 2(b^2+a^2)/((b+a)^2(b-a))

Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

4 0

2 years ago

Solve for A if F=MA and F=10 and M=2.5

gogolik [260]

Answer:

$\boxed{\sf A = 4}$

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

$\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:$

$\sf \implies 10 = 2.5A$

$\sf \implies 2.5A = 10$

$\sf Dividing \ both \ side \ of \ 2.5A = 10 \ by \ 2.5:$

$\sf \implies \frac{2.5}{2.5} A = \frac{10}{2.5}$

$\sf \frac{2.5}{2.5} = 1 :$

$\sf \implies A = \frac{10}{2.5}$

$\sf \frac{4 \times \cancel{2.5}}{ \cancel{2.5}} = 4 :$

$\sf \implies A = 4$

3 0

3 years ago

Read 2 more answers