Answer:
- 6.04 km (per angle marks)
- 5.36 km (per side hash marks)
Step-by-step explanation:
Going by the angle indicators, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 4200/3500
x = 2000·6/5 = 2400 . . . . yards
Then the distance of interest is ...
(2400 yd + 4200 yd)×(0.0009144 km/yd) = 6.6×.9144 km
= 6.03504 km ≈ 6.04 km
_____
Going by the red hash marks, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 3500/4200
x = 2000·(5/6) = 5000/3 . . . . yards
Then the distance of interest is ...
(5000/3 + 4200) yd × 0.0009144 km/yd ≈ 5.36 km
_____
<em>Comment on the figure</em>
The usual geometry here is that the outside legs (opposite the vertical angles) are parallel, meaning that the angle indicators are the correct marks. It is possible, but unusual, for the red hash marks to be correct and the angle indicators to be mismarked. The red hash marks seem tentatively drawn, so seem like they're more likely to be the incorrect marks.
Answer:
6
Step-by-step explanation:
all you have to do is 30 / 5 what equals 6
Answer:
40 2/5Ibs or 
lbs
Step-by-step explanation:
Let weight of object on the moon be represented = Wm
weight of object on the Earth = We
In the above question, we are told:
The weight of an object on the moon is
5 of its weight on Earth.
Hence, mathematically, this is represented as:
5Wm = We
If a moon rock weighs 202 lbs on Earth
5Wm = 202lbs
Wm = 202lbs/5
Wm = Ibs
Therefore, the moon rock weighs Ibs on the moon.
Answer: x=-1
Step-by-step explanation:
