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Vladimir79 [104]
4 years ago
7

Que cambiaría personalmente en esos momentos de cuarentena​

Computers and Technology
1 answer:
Natali5045456 [20]4 years ago
6 0
No poder salir sin estar con la duda de que si una persona con la que estas cercas tendría el virus , no poder visitar a ciertas personas
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Who would use a magnetic hard drive? Give a scenario and include examples as well as detail.
dybincka [34]
A magnetic hard drive well all hardrives have a magnet n them id say if it was to withstand heat so it whould stay on the magnet therefore not compromising the data <span />
3 0
4 years ago
I need someone's opinion<br> Which format is better? The first or second one? I can't decide 0.0
Ne4ueva [31]

Answer:

2nd one

Explanation:

4 0
3 years ago
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A machine is classified as a compound machine if it?
HACTEHA [7]
Composed of more than 1 simple machine
3 0
4 years ago
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(JAVA PLS)
Elza [17]

import java.util.Scanner;

public class JavaApplication54 {

   public static int appearance(String word, char letter){

       int count = 0;

       for (int i = 0; i < word.length(); i++){

           if (word.charAt(i) == letter){

               count++;

           }

       }

       return count;

   }

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Type the message to be shortened");

       String message = scan.nextLine();

       message = message.toLowerCase();

       int volCount = 0, repCount = 0, num = 0;

       char prevC = ' ';

       String vowels = "aeiou";

       String newMessage = "";

       for (int i = 0; i < message.length(); i++){

           char c = message.charAt(i);

           

           if (vowels.indexOf(c) != -1 && prevC == ' '){

               newMessage += c;

           }

           else if (vowels.indexOf(c) == -1 && prevC != c){

               newMessage += c;

           }

           else if (vowels.indexOf(c) != -1){

               volCount ++;

           }

           else{

               repCount++;

           }

            prevC = c;

       }

       System.out.println("Algorithm 1");

       System.out.println("Vowels removed: "+volCount);

       System.out.println("Repeats removed: "+repCount);

       System.out.println("Algorithm 1 message: "+newMessage);

       System.out.println("Algorithm 1 characters saved: "+(message.length() - newMessage.length()));

       

       String uniqueMessage = "";

       

       for (int i = 0; i<message.length(); i++){

           char w = message.charAt(i);

           if (uniqueMessage.indexOf(w)== -1 && w!=' '){

               uniqueMessage += appearance(message,w)+""+w;

               num++;

           }

       }

       System.out.println("Algorithm 2");

       System.out.println("Unique characters found: "+num);

       System.out.println("Algorithm 2 message: "+uniqueMessage);

       System.out.println("Algorithm 2 characters saved: "+(message.length() - uniqueMessage.length()));

   }

   

}

I hope this helps!

6 0
3 years ago
Use search engines and websites to research the following WAN technologies to complete the table below:
Yuki888 [10]

Answer:

Explanation:

I am attaching the table as an image with updated table containing required information for the following WAN technologies.

T1/DS1 => Digital Signal 1 (T-Carrier 1),

T3/DS3 => Digital Signal 3 (T-Carrier 3),

OC3 (SONET) => Optical Carrier 3 (Synchronous Optical Networking),

Frame Relay,

ATM => Asynchronous Transfer Mode,

MPLS => Multi-protocol Label Switching,

EPL => Ethernet Private Line.

Although you have mentioned most of the information yourself, there were some wrong data in it.  So I have updated them with correct information in the attached table.

4 0
3 years ago
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