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nata0808 [166]
3 years ago
6

2. Factorizar: 3ax – 3ay – 2bx + 2byhelp please :(

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

There are no like terms.

Step-by-step explanation:

basically that is your answer you can not solve so it will be 3ax – 3ay – 2bx + 2by

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The diagram shows a rectangle and a diagonal of the rectangle. Length=8.5cm. Width=5.6cm. Work out the length of the diagonal of
zhenek [66]

Answer:

10.2cm

Step-by-step explanation:

Diagonal= √8.5^2 + 5.6^2

=10.2cm

8 0
3 years ago
David drove 580 km on 7 hour journey. on the city roads he drove 60km/h and on the he drove 100km/h. How long did he drive at ea
serious [3.7K]

Answer:

3 hours on the city roads and 4 hours on the other roads

Step-by-step explanation:

580 (total miles driven) - 400 (4 hours of driving 100km/h) = 180 (miles left)

180 (miles left to drive) / 60 (km/h) = 3 (hours driven at the speed of 60km/h)

I hope this helps :)

5 0
3 years ago
Write the equation x = -2/7y + 3/4 in standard form
babunello [35]
Standard form is presented as Ax + By = C

all you need to do here is move the y value over to the side with the x value.

so,

x + 2/7y = 3/4
3 0
3 years ago
How do you solve (3c)³ - (c - 4d)²; c = -2 AND d = 5
algol13
You just plug in the values.

[3*(-2)]^3 - (-2 - 4*5)^2

(-6)^3 - ( - 2 - 20)^2

-216 - (-22)^2

-216 - (484)

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8 0
3 years ago
Riley buys office equipment with a total price of $6,280 for her new company. If the office equipment depreciates at a rate of 1
alexdok [17]

Answer: y = 6280(0.87)^x

Step-by-step explanation:

If the office equipment depreciates at a rate of 13% each year, then the rate of depreciation is exponential.

We would apply the formula for exponential decay which is expressed as

y = b(1 - r)^x

Where

y represents the value of the office equipment after t years.

x represents the number of years.

b represents the initial value of the office equipment.

r represents rate of decay.

From the information given,

y = $628

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Therefore, the equation that represents the value of the equipment after x years is

y = 6280(1 - 0.13)^x

y = 6280(0.87)^x

4 0
3 years ago
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