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rodikova [14]
2 years ago
13

Doing some review on PEMDAS. I just need help to know if I am on the right track with this problem.

Mathematics
2 answers:
juin [17]2 years ago
3 0
Yes! You’re on the right track! You followed it perfectly!
Parentheses
Exponent
Multiplication
Division
Addition
Subtraction

Well done!
lina2011 [118]2 years ago
3 0

Answer:

The order in which you evaluated the expression was a bit incorrect but the outcome either way was 78. In some cases if you evaluate the expression incorrectly or not in order will result in you getting the wrong answer. If you want to see how to evaluate it correctly just look below.

Step-by-step explanation:

PEMDAS stands for

Parenthesis

Exponents

Multiplication and Division ( left to right )

Addition and Subtraction ( left to right )

And it basically tells us the order in which you are suppose to evaluate a mathematical expression.

It appears the expression you are given is 4² + ( 1 × 5 + 7² ) + 8

First we would do the operation inside of the parenthesis

so we have ( 1 × 5 + 7² )

Exponents come before multiplying and addition so first evaluate the exponent, 7² = 49

we now have ( 1 × 5 + 49 )

we next do the multiplication

( 5 + 49 )

Finally we do the addition

5 + 49 = 54.

We then replace the expression ( 1 × 5 + 7² )  with 54 as we just evaluated everything in the parenthesis

we get 4² + 54 + 8

So we just did the parenthesis and next is exponents so lets evaluate the exponents, 4² = 16

16 + 54 + 8

Next in PEMDAS is multiplication and division. There is none so we go to the next step.

We now do the addition and subtraction. ( going left to right )

16 + 54 + 8

first add 16 and 54

70 + 8

finally add 70 and 8

= 78

Notes:

For parenthesis you evaluate everything inside of the parenthesis before you remove the parenthesis

For multiplcation and division, you must evaluate in order going left to right, not doing so can result in a wrong answer.

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Devin grew 12 flowers with 3 seed packets. How many seed packets does Devin need to have a total of 20 flowers in his garden? As
Whitepunk [10]
If he grew 12 flowers with 3 seed packets then there should be 4 seeds in one packet > 3 x 4 = 12
Devin needs 5 seed packets to have a total of 20 flowers in his garden
> 4 x 5 = 20
7 0
2 years ago
Which inequality is graphed below
Vaselesa [24]

Answer:

3x-2y < 6

Step-by-step explanation:

First of all, we need to identify the equation of the line. x and y intercepts are known, so we can quickly write the line as

\frac x 2 + \frac y{(-3)} = 1 \rightarrow 3x-2y=6 That gives us the last two options. To solve it let's plug a convenient point - read: the origin - into the equation and see which one holds true. And since for obvious reason 3\cdot 0 -2 \cdot 0 =0 < 6 the valid solution is the last one.

6 0
2 years ago
4. The results of testing a new drug on 1,000 people with a certain disease found that 510 of them improved when they used the d
Shalnov [3]

Answer:

It would not be reasonable to say that  more than half of the people with this disease would  improve if they used the new drug

Step-by-step explanation:

Data provided in the question:

Sample size,  n = 1000

Number of people improved when they used the drug = 510

Thus,

Probability that Number of people improved when they used the drug

= 510 ÷ 1000

= 0.510

Now,

margin of error, E = 2\times\sqrt{\frac{p(1-p)}{n}}

= 2\times\sqrt{\frac{0.510(1-0.510)}{1000}}

= 0.032 = 3.2%

Therefore,

Portion of 0.510 is likely to lie in the 3.2% of the actual value of population

And,

The lower portion can be as small as p - E

= 0.510 - 0.032

= 0.478 i.e 47.8% of the sample

Hence,

It would not be reasonable to say that  more than half of the people with this disease would  improve if they used the new drug

4 0
3 years ago
Whats your yes and no
Elza [17]
Yes I love cookies no I don’t like math
8 0
2 years ago
1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15
Inessa [10]

Answer:

\frac{4+16a^3+23a^3}{a^2}

Step-by-step explanation:

Given

1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15

Required

Simplify

1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15

Collect Like Terms

1/a^2 + 1/a^2 + 2/a^2-3a-5a-8a+2+6+15

1/a^2 + 1/a^2 + 2/a^2-16a+23

Add Fractions:

\frac{1+1+2}{a^2} + 16a + 23

\frac{4}{a^2} + 16a + 23

This can be further expressed as:

\frac{4+16a^3+23a^3}{a^2}

4 0
2 years ago
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