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GrogVix [38]
1 year ago
15

Please answer need to turn it in please help me answer

Mathematics
1 answer:
Elena-2011 [213]1 year ago
4 0

Answer: Sir in what way would you like me to explain this

Step-by-step explanation:

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Hilda runs 2/3 of a mile in a half-hour. If she continues to run at a constant rate, how many miles will she run in 3 hours?
Naddika [18.5K]
2/3 a mile in half an hour
3 hours=6 x 2/3
6/1 x 2/3 = 12/3
12/3 =4 miles in 3 hours
5 0
3 years ago
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Thepotemich [5.8K]

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I think it will be $16.50

Step-by-step explanation:

sorry if I'm wrong

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3 years ago
¿Cuáles son los números primos entre 2 y 20?
Rus_ich [418]

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Step-by-step explanation:

6 0
2 years ago
Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the
guapka [62]

Answer:

The maximum number of packages that can be made  with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

<em>To find the G.C.F., we will list down the prime factors of each.</em>

48=2\times 2\times 2\times 2\times 3

30=2\times 3\times 5

We find that the G.C.F. = 2\times 3 = 6

Thus, the maximum number of packages that can be made  with each package have same number of each item is = 6

4 0
3 years ago
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
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