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2 years ago

Choose the product. (3x 2 + 2x - 3)(x - 1)

1 answer:

6 0

(3x² + 2x - 3) (x-1),

The product of the above factors is: 3x³ - x² - 5x + 3

Distributive property of multiplication

x(3x² + 2x - 3) - 1(3x² + 2x - 3)
3x³ + 2x² - 3x - 3x² - 2x + 3

Group like terms:
3x³ + 2x² - 3x² - 3x - 2x + 3
3x³ - x² - 5x + 3

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Would you classify the number 289 as a perfect square, perfect cube, both, or neither?

Black_prince [1.1K]

Answer:

a perfect square because 17 x 17 = 289

It's not a perfect cube

Step-by-step explanation:

7 0

2 years ago

In ∆GHI, the measure of I=90°, the measure of G=82°, and GH = 3.4 feet. Find the length of HI to the nearest tenth of a foot.

natka813 [3]

Answer: 3.4

Step-by-step explanation:

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2 years ago

Simplify this equation Thanks a lot!!!

den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

$\bf\implies a^m \times b^m = (ab)^m$

Using this property , we have ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

This can be written as ,

$\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}$

Simplifying using ( a+b)(a-b) = a² - b² ,

$\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}$

Subtracting the numbers inside the brackets ,

$\rm\implies (-1)^{2n - 1 }$

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the power is odd .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

$\rm\implies\boxed{\quad \red{ -1 }\quad }$

Hence the required answer is (-1) .

4 0

2 years ago

Which of the following is the quotient of rational expressions shown below?

emmasim [6.3K]

Answer: 6x - 3 over x^3

Step-by-step explanation:

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2 years ago

How do I rotate a figure 90 degrees clockwise

cricket20 [7]

Step-by-step explanation:

You have to have tracing paper or patty paper (cause that's what my teacher uses). Next you draw the figure along with the x and y-axis on it as well. Then you mark the x and y-axis and rotate the paper 90 degrees clockwise. Lastly if the x-axis is on the y-axis, mark it as the y-axis and if the y-axis is on the x-axis, also mark it as the x-axis.

I hope this helped :)

5 0

2 years ago