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TEA [102]
3 years ago
7

20pts Please help! Asap Visitor attendance at the nature center in December is one-quarter the attendance in September. In Decem

ber, 94 people visit the nature center. How many people visit the nature center in September?
Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer: I am in 6th grade and I just did this test too at K12 CAVA. I got the answer correct, it is:

376

Hope this helps.




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Which of the following represents "the difference between ten and a number is the sum of eight and a number"?
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10 - N = 8 + N
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5929×2959-300+900=________
miskamm [114]

Answer:17,544,511

Step-by-step explanation: 5929 x 2959= 17,543,911

17,543,911-300= 17,543,611

17,543,611 + 900 = 17,544,511

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WILL MARK THE FIRST BRAINLY ANSWER!
ehidna [41]

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A quadrant 1

Step-by-step explanation:

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3 0
3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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