A student wrote a number pattern such that each number is 3 more that 4 times the previous number. What is the sixth term in the
pattern if the first term is 6?
2 answers:
1st term = 6
2nd term = 24+ 3
3nd term = 111
4th term = 447
5th term = 1791
6th term = 7167
Is there a simplified formula?
Start with 1.
1st number = 1
2nd number = 1 * 4 + 3 = 7
3rd number = 7 * 4 + 3 = 31
4th = 31 * 4 + 3 = 127
5th = 127 * 4 + 3 = 511
Which means the 6th = 511 * 4 + 3, which is 2047.
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