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Snezhnost [94]
3 years ago
13

PTG has side lengths of 18 cm, 27 cm, and 13 cm. which type of triangle is PTG? The answer is obtuse.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0
To know what kind of triangle is it. use the pythagorean theorem:
A^2 + B^2 = C^2,
where C is the longest side of the triangle 
if it satisfies the equation then it is a right triangle
if it does not then A^2 + B^2 > C^2 so it is acute triangle
if A^2 + B^2 < C^2 it is obtuse triangle

18^2 + 13^2 ? 27^2
324 + 169 ? 729
493 < 729 so it is obtuse triangle

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Can someone help idk if this is right
navik [9.2K]

Answer:

a_n=-3 \cdot a_{n-1}

a_1=2

You gave the explicit form.

Step-by-step explanation:

You gave the explicit form.

The recursive form is giving you a term in terms of previous terms of the sequence.

So the recursive form of a geometric sequence is a_n=r \cdot a_{n-1} and they also give a term of the sequence; like first term is such and such number. All this says is to get a term in the sequence you just multiply previous term by the common ratio.

r is the common ratio and can found by choosing a term and dividing by the term that is right before it.

So here r=-3 since all of these say that it does:

-54/18

18/-6

-6/2

If these quotients didn't match, then it wouldn't be geometric.

Anyways the recursive form for this geometric sequence is

a_n=-3 \cdot a_{n-1}

a_1=2

5 0
3 years ago
8+9x1x2 to the second power it has the 2 above the 2 but I just can't put it there on this
Gnoma [55]
The correct answer is 44
8 0
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10/5 POINTSSSSSS!!!!!
Yanka [14]
It's b 1/9 mile i thank

8 0
3 years ago
A pedestrian walks 7.4 kilometers west
attashe74 [19]

Answer: 11.8 km

Step-by-step explanation:

The resulting figure is a right angled triangle shown below

$$Apply the Pythagorean theorem to find out the magnitude of the resultant vector $A B$ in the triangle $A B C$ as follows -$$\begin{aligned}&A B^{2}=B C^{2}+C A^{2} \text { (Hypotenuse }{ }^{2}=\text { Base }^{2}+\text { Adjacent }^{2} \text { ) } \\&=7.4^{2}+9.2^{2} \\&=139.4 \\&A B=11.806777 \\&\quad A B \approx 11.8 \mathrm{~km} \text { (Rounded off to the nearest tenth) }\end{aligned}$$

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2 years ago
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IRISSAK [1]

the answer is above.

3 0
3 years ago
Read 2 more answers
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