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FinnZ [79.3K]
2 years ago
14

How many ways can you flip a coin and roll a standard dice?

Mathematics
1 answer:
ozzi2 years ago
7 0

Answer:

its probably 6×2=12 times

coin has 2 sides

dice has 6 faces

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Can you help me on this?
Illusion [34]

Answer:

y = 30

Step-by-step explanation:

We can use ratio's to solve this

40        20

-----  = -----------

100       20 + y


Using cross products

40 * (20+y) = 20*100

Distribute

800 + 40y = 2000

Subtract 800 from each side

40y = 2000-800

40y = 1200

Divide by 40

y = 1200/40

y =30

5 0
3 years ago
Abdul has 15 shirts to fold. Let n be the number of shirts he would have left to fold after folding f of them. Write an equation
andrew-mc [135]

Answer:

n + f = 15

Step-by-step explanation:

n + f = 15

n + (6) = 15

n = 15 - 6 (opposite side opposite sign)

n = 9

4 0
2 years ago
What is the remainder when thirty-eight is divided by four?
Alika [10]
The answer is 9.5 so the remainder would be 5
7 0
2 years ago
A bag contains red balls and white balls. If five balls are to be pulled from the bag, with replacement, the probability of gett
Ipatiy [6.2K]

Answer:

Percentage of balls which are red = 80%.

Step-by-step explanation:

Let the probability of drawing a red ball  be x then the probability of drawing a white ball is 1-x.

There are 5C3 = 10 ways of getting 3 reds in 5 draws so  the probability of this is 10* x^3 * (1 - x)^2.

The probability of getting 1 red in 5 draws = 5C1 * x (1-x)^4.

The  first probability is 32 times the last.

So we have the equation:

10x^3(1 - x)^2  /  5x(1 - x)^4  = 32

2x^2 / (1 - x)^2 = 32

2x^2 = 32(1 -x)^2

2x^2 = 32( 1 - 2x + x^2)

2x^2 = 32 - 64x + 32x^2

30x^2 - 64x  + 32 = 0

15x^2 - 32x + 16 = 0

(5x - 4)(3x - 4) = 0

x = 0.8, 1.333...

The probability must be < 1 so x = 0.8  = 80%.

6 0
3 years ago
I need help with this equation <br> 2+38-1•74
Pepsi [2]

Answer:38.26 because 2+38=40

40-1.74 =38.26

3 0
2 years ago
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