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weqwewe [10]
3 years ago
11

A zoo has two male lions 1/6 of the line on male lions how many lions are there at the zoo

Mathematics
1 answer:
natulia [17]3 years ago
7 0
2 is 1/6 of ?
6x2=12
12 lions in total
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Step-by-step explanation:

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Which graphs have rotational symmetry? Check all that apply
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Answer:

Option A and C have rotational symmetry.

Step-by-step explanation:

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A function is "odd"  when we plug in any negative value in f(x) then it gives negative of f(x).

And we also know that when a graph is mirroring about the y-axis then it is an even functions.

For even functions we have reflection symmetry rather than rotational symmetry.

The second graph is a graph of f(x)=-modulus (x) which is an even function as we can see that its graph is mirroring about the y-axis.

The third graph is a graph of an ellipse which is possessing  rotational symmetry.

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Order of symmetry:

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A data set includes data from student evaluations of courses. The summary statistics are nequals83​, x overbarequals3.32​, sequa
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Answer:

Hypothesis

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

The degrees of freedom are given by:

df=n-1=83-1=82

And the p value would be given by:

p_v =2*P(t_{(82)}    

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

\bar X=3.32 represent the sample mean

s=0.56 represent the sample deviation

n=83 sample size    

\mu_o =3.5 represent the value to test

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:    

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing we got:

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

The degrees of freedom are given by:

df=n-1=83-1=82

And the p value would be given by:

p_v =2*P(t_{(82)}    

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0
3 years ago
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