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mr Goodwill [35]
4 years ago
15

0.6 is the cube root of what value

Mathematics
2 answers:
Delvig [45]4 years ago
8 0
Is there choices ? I got 0.216
egoroff_w [7]4 years ago
8 0
Take 0.6 and then take it to the power of 3.
(0.6)^3 = 0.126
So the answer is 0.126
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Even number between 3 and 9
vodka [1.7K]

Answer:4, 6, 8,

Step-by-step explanation:

odd numbers 1,3,5,7,9,11

even numbers 2,4,6,8,10

7 0
4 years ago
Read 2 more answers
What is the algebric expression of z is greater than y by ten
stiv31 [10]
Z = y + 10

I’m not sure if this is the equation you are looking for, but saying that “Z” is equal to “y + 10” is like saying that “Z” is greater than “y” by ten.

I hope this helped! ☻
3 0
3 years ago
​a) If the null hypothesis is​ true, you'll get a high​ P-value. ​b) If the null hypothesis is​ true, a​ P-value of 0.01 will oc
maxonik [38]

Answer:

​a) If the null hypothesis is​ true, you'll get a high​ P-value. ​(it depends)

b) If the null hypothesis is​ true, a​ P-value of 0.01 will occur about​ 1% of the time. (false)

​c) A​ P-value of 0.90 means that the null hypothesis has a good chance of being true. ​(not only has a good chance it has strong evidence)

d) A​ P-value of 0.90 is strong evidence that the null hypothesis is true.(true)

Step-by-step explanation:

Before i answer this question, you need to understand that p-values give you the clues to identify when you can <u>accept the null hypothesis ( null hypothesis is true)</u> and when you can r<u>eject the null hypothesis (null hypothesis is not true).</u>

<u />

1. When you get a small p-value  (typically ≤ 0.05) values that are less or equal to 0.05, for example 0.01,  you reject the null hypothesis (null hypothesis is not true)

2. when you get a large p-value (> 0.05) values that are greater than 0.05, for example 0.94, 0.90. you can accept the null hypothesis because  indicates weak evidence against the null hypothesis (null hypothesis is true).

<u> This is the explanation:</u>

<u />

a) if the null hypothesis is true  you`ll get a high p-value<u> only if the p-value is ≥ 0.05</u>

b) if p value is less or equal to 0.05. Null hypothesis is not true.

c) A​ P-value of 0.90 means that the null hypothesis has a good chance of being true . It not only has a good chance it is strong evidence that null hypothesis is true.

d) A p-value of 0.90 is strong evidence that null hypothesis is true. p-values that are greater than 0.05  you can accept the null hypothesis (null hypothesis is true).

<u></u>

7 0
3 years ago
How do I find the dilation, though it’s not on a graph ?
OleMash [197]
Just half each side and keep point a at the same position
5 0
4 years ago
Solve and show the steps to the picture attached
lina2011 [118]

Answer:

The image of point (2, 4) after transformation is (-2, 13) ⇒ D

Step-by-step explanation:

Let us revise some transformation

Translation right-left OR up-down

  • If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)  ⇒ add x-coordinate of every point by h
  • If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)   ⇒ subtract x-coordinate of every point by h
  • If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k  ⇒ add y-coordinate of every point by k
  • If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k  ⇒ subtract y-coordinate of every point by k

A vertical stretching and a vertical compression (or shrinking)

  • If m > 1, the graph of y = m • f(x) is the graph of f(x) vertically stretched by factor m.  ⇒ multiply every y-coordinate by m
  • If 0 < m < 1 (a fraction), the graph of y = m • f(x) is the graph of f(x) vertically shrunk (or compressed) by factor m  ⇒ multiply every y-coordinate by m

Let us use these rules to solve the question.

∵ Point (2, 4) lies on y = x²

∵ The image of y = x² is y = 3(x + 4)²+1

→ The rules of transformation is y = m(x + h)² + k

∵ m is the scale factor of a vertical stretched

∵ m = 3

→ By using the 5th rule above

∴ The y-coordinate of point (2, 4) should multiply by 3

∴ The image of the point is (2, 4 × 3) = (2, 12)

∵ h is the horizontal translation to the left

∵ h = 4

→ By using the 2nd rule above

∴ The x-coordinate of point (2, 12) should subtract by 4

∴ The image of the point is (2 - 4, 12) = (-2, 12)

∵ k is the vertical translation up

∵ k = 1

→ By using the 3rd rule above

∴ The y-coordinate of point (-2, 12) should add by 1

∴ The image of the point is (-2, 12 + 1) = (-2, 13)

∴ The image of point (2, 4) after transformation is (-2, 13)

3 0
3 years ago
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