The rays OM , ON , and OP in the figure, coincide at time t=0. At the same instant of time OM and OP rotate in the plane about p
oint O in opposite directions while ON remains fixed. With respect to ON , segment OM rotates at constant rate of 3° per second and OP , at 6° per second. What is the smallest positive value of t, in seconds, for which segments OM and OP will coincide? When t=30 min, how many more revolutions does segment OP complete than segment OM ?
OM and OP will coincide a second time after 120 seconds. You could visualize it as ray OP moving at 3 degrees/second relative to OM. Using this visualization, we find that OM makes 30*60*3/360 rotations (minutes * 60 * rotational speed/360 degrees in a rotation), which is 15, and that OP makes 30*60*6/360 or 30 rotations, which is 15 more than OM.
4x=9y+2 x=(9y+2)/4 11x-8=90+9y+2 11((9y+2)/4)-8=9y+92 (99y+22)/4=9y+100 99y+22=36y+400 63y=378 y=6 x=14 is the question asking for y or x？？or is it asking for angle
