Is 1.34 a non-terminating decimal
2 answers:
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Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution:
Where is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:
Substitute the respective values in the above formula.
Hence, the required probability is 0.55404.