1 1 1 2
2 -3 1 -11 -2R1 + R2 → R2
-1 2 -1 8 R1 + R3 → R3
1 1 1 2
0 -5 -1 -15 R2 ⇔ R3
0 3 0 10
1 1 1 2
0 3 0 10 -R3
0 -5 -1 -15
1 1 1 2
0 3 0 10 1/3 R2
0 5 1 15
1 1 1 2 -R2 + R1
0 1 0 10/3 -5R2 + R3
0 5 1 15
1 0 1 -4/3
0 1 0 10/3 -R3 + R1
0 0 1 -5/3
1 0 0 1/3
0 1 0 10/3
0 0 1 -5/3
Therefore, x = 1/3, y = 10/3, z = -5/3
Answer:nah
Step-by-step explanation:
You must first normalize this in order to use a Z-score table. To convert what you have into a Z score you must use this formula: (x- mean) /standard deviation. In your case (334-310)/12=2. So now you want the probability that a score is greater than 334, which in turn means you want P(Z>2)=1-P(Z<2)=1-.9772=0.0228=2.28%.
Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6
Therefore...
Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11
