Answer:
Total possible ways to select 6 teachers from 34 teacher are
.
Step-by-step explanation:
It is given that total number of teachers at a school is 34.
The school director must randomly select 6 teachers to part in a training session.
![^nC_r=\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5EnC_r%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Where, n is total possible outcomes and r is number of selected outcomes.
Total teachers = 34
Selected teachers =6
Total number of possible ways to select 6 teachers from 34 teacher is
![^{34}C_6=\frac{34!}{6!(34-6)!}](https://tex.z-dn.net/?f=%5E%7B34%7DC_6%3D%5Cfrac%7B34%21%7D%7B6%21%2834-6%29%21%7D)
![^{34}C_6=\frac{34\times 33\times 32\times 31\times 29\times 28!}{6!(28)!}](https://tex.z-dn.net/?f=%5E%7B34%7DC_6%3D%5Cfrac%7B34%5Ctimes%2033%5Ctimes%2032%5Ctimes%2031%5Ctimes%2029%5Ctimes%2028%21%7D%7B6%21%2828%29%21%7D)
![^{34}C_6=1344904](https://tex.z-dn.net/?f=%5E%7B34%7DC_6%3D1344904)
Therefore total possible ways to select 6 teachers from 34 teacher are
.
Answer:
Option (1)
Step-by-step explanation:
By the inscribed angle theorem inside a circle,
"Measure of an inscribed angle is half the measure of the intercepted arc"
[m(arc AB)] = m(∠ABC)
m(arc AB) = 2[m(∠ABC)]
x = 2(41°)
x = 82°
Option (1) is the correct option.
Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
=========================================================
Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
--------
To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.