Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x-(3*x^3+8*x^2+5*x-7)=0
Step by step solution :Step 1 :Equation at the end of step 1 : x-((((3•(x3))+23x2)+5x)-7) = 0 Step 2 :Equation at the end of step 2 : x - (((3x3 + 23x2) + 5x) - 7) = 0 Step 3 :Step 4 :Pulling out like terms :
4.1 Pull out like factors :
-3x3 - 8x2 - 4x + 7 =
-1 • (3x3 + 8x2 + 4x - 7)
Checking for a perfect cube :
4.2 3x3 + 8x2 + 4x - 7 is not a perfect cube
Trying to factor by pulling out :
4.3 Factoring: 3x3 + 8x2 + 4x - 7
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3x3 - 7
Group 2: 8x2 + 4x
Pull out from each group separately :
Group 1: (3x3 - 7) • (1)
Group 2: (2x + 1) • (4x)
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I believe the answer is B) 50
Answer:
x = 15.65
y = 3.5
Step-by-step explanation:
Step 1
Find the equation for x and y
Equation for x is given as
x² = 7( 7+28) ..........Equation 1
14(14 + y) = x²........ Equation 2
Solving for Equation 1
x² = 7( 7+28)
x² = 7(35)
x² = 245
x = √245
x = 15.65
From Equation 1 , x² has been determined to be 245
Therefore we substitute 245 for y in Equation 2
14(14 + y) = x²........ Equation 2
14(14 + y) = 245
196 + 14y = 245
14y = 245 - 196
14y = 49
y = 49 ÷ 14
y = 3.5
Answer:
152.16 yd²
Step-by-step explanation:
2(8 x 5.6) + 2(8 x 2.3) + (2.3 x 8) = 152.16 yd²
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So the Pythagorean triplet is 8,15and 17