For this case we must solve the following quadratic equation:

With
we have:

The roots will be given by:

Where:

Substituting:

Thus, we have two roots:

Answer:

Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
A and D
Step-by-step explanation:
53 + 37 + 44 with the time standard being minutes
Find total time
___________________________________________
We have units of time and need to add them together, let's do as such.
53 + 37 + 44
134 minutes.
Let's try simplifying it into minutes to find how much we have :
134/60
2 hours and 14 minutes
Therefore A and D are correct.
Answer:
-41/10, -42/10, -43/10, -45/10
Step-by-step explanation:
multiply with 10 in numerator and denominator in -5/1 and -4/1
-5×10/1×10 , -4×10/1×10
you will get,
-50/10 , -40/10
now u can find the four rational numbers
four rational no's: -41/10, -42/10, -43/10, -45/10
hope u understood:)
Answer: Just simply solve the problem, i'm sorry but i cant see the problem do you think you could just copy the question down?
Step-by-step explanation: