How to solve log base 5 of x + log base 5 of (4x-1)
1 answer:
Log5(x)+log5(4x-1)
As the bases are the same the number doesn't matter
Log (a) + log(b) =log (ab)
Log(4x^2-x)
(x )(4x-1)
x=0.25 or x=0
Log(4×0.25^2-0.25) = log(0) = Infinity
Same with 0. So no answer
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