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astraxan [27]
2 years ago
6

Write the equation of a line that passes the point (-6,9)and is perpendicular to a line that passes through the points (-2,1) an

d (6,7).
Mathematics
1 answer:
Vanyuwa [196]2 years ago
4 0

Answer:

hope you like my answer its-11

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Y=3/2x+3 <br> y=-3 solve.
laila [671]
Answer : x= -4

This type of problem, you set them equal to each other. And then solve. Don’t forget you can multiply each side by denominator to eliminate the fraction.
Work:

7 0
3 years ago
Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
Volgvan

The equation of the circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

r=10\\(-3,\ 6)\to h=-3,\ k=6

Substitute:

(x-(-3))^2+(y-6)^2=10^2\\\\(x+3)^2+(y-6)^2=100

4 0
3 years ago
Anyone know the answer?
olganol [36]
The last answer choice
5 0
4 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
Lura’s chocolate bar is 71% cacoa. If the weight of the chocolate bar is 58 grams, how many grams of cocoa does it contain? Roun
gtnhenbr [62]
58*0.71= around 41.2 grams of coco. This is because we can multiply to get this.

Please like and brainiest if correct!
4 0
2 years ago
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