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kow [346]
3 years ago
12

In the pendulum formula, we use g=9.8 m/s^2 for the acceleration due to gravity on Earth. But what about on Venus? If an astrona

ut on the surface of Venus swings a 1-meter long pendulum, and it has a period of 2.11 seconds, what is the acceleration due to gravity, g, on Venus?

Mathematics
2 answers:
kherson [118]3 years ago
6 0

Answer:

Option A is the correct answer.

Step-by-step explanation:

Period of simple pendulum is given by the expression,

            T=2\pi \sqrt{\frac{l}{g}}

Where l is the length of pendulum, g is acceleration due to gravity.

Here given for Venus

         Period, T = 2.11 s

        Length of pendulum, l = 1 m

     We need to find acceleration due to gravity, g

Substituting

            2.11=2\pi \sqrt{\frac{1}{g}}\\\\\sqrt{g}=\frac{2\pi}{2.11}\\\\g=8.87m/s^2

Acceleration due to gravity of Venus = 8.9 m/s²

Option A is the correct answer.

Vikentia [17]3 years ago
5 0

Answer:

8.9 (just got it on Apex)

Step-by-step explanation:

(guessed correct on Apex due to other questions on Brainly that were relative to this one)

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