Question

In the pendulum formula, we use g=9.8 m/s^2 for the acceleration due to gravity on Earth. But what about on Venus? If an astronaut on the surface of Venus swings a 1-meter long pendulum, and it has a period of 2.11 seconds, what is the acceleration due to gravity, g, on Venus?

Answer 1

Answer:

Option A is the correct answer.

Step-by-step explanation:

Period of simple pendulum is given by the expression,

            $T=2\pi \sqrt{\frac{l}{g}}$

Where l is the length of pendulum, g is acceleration due to gravity.

Here given for Venus

         Period, T = 2.11 s

        Length of pendulum, l = 1 m

     We need to find acceleration due to gravity, g

Substituting

            $2.11=2\pi \sqrt{\frac{1}{g}}\\\\\sqrt{g}=\frac{2\pi}{2.11}\\\\g=8.87m/s^2$

Acceleration due to gravity of Venus = 8.9 m/s²

Option A is the correct answer.

Answer 2

Answer:

8.9 (just got it on Apex)

Step-by-step explanation:

(guessed correct on Apex due to other questions on Brainly that were relative to this one)