Answer: 24≤ a < 26
Step-by-step explanation:
The modal class interval is the class interval with the highest frequency, the highest frequency from the table is 8 , which belongs to the class interval 24≤ a < 26
A.
the area of a polygon is/
A= perimeter X apothem /2
A=500
apothem = 10
500 = (P * 10)/2
P =100
B. 100*7.95 = $795
C.
60*100= 6,000
6,000 * $7.95=
<span>$47,520</span>
Answer:400 miles per hour
Step-by-step explanation:
Let w = speed at which the plane travelled west
Let s = speed at which the plane travelled south
Distance moved in 5 hrs heading west = 5*w = 5w
Distance moved in 4 hrs heading south = 4*s = 4s
Total distance, 3444= 5w + 4s
w = s + 39( 39 miles/hr faster)
5(s+39) + 4s = 3444
5s + 195 + 4s = 3444
9s = 3249
s = 361 miles per hour
w = s + 39 = 361 +39
= 400 miles per hour
Y ≥ 2x-5
y-intercept is -5, from there go 2 up 1 over ( slope is rise over run)
greater than or equal so the line is connected
now find the shaded area by plugging in (0,0)
0 ≥2(0)-5
0 ≥-5 is correct so shade the area that to the left of the line, (the whole area that including (0,0))
y<-3x
y intercept is 0 so start from there and go down 3 right 1 (or go up 3 left 1)
broken like cause no or equal sign
the (0,0) is on the line so use (1,1) to find the answer
1<-3(1) is incorrect so shade the area that dies not include (1,1) or the entire area to the left of that line
you can see the section where both shaded area cross, thats the answer so erase every area you shaded that isn’t the answer so
THE ANSWER IS C
Answer:
<h3>11.8 feet</h3>
Step-by-step explanation:
Given
Length of the ladder = 12foot
angle of elevation = 80 degrees
Required
Height of the wall (opposite side)
The set up will form a right angled triangle where
length of the ladder is the hypotenuse
height of the wall is opposite;
Using SOH, CAH, TOA trig identity
According to SOH
sin 80 = opp/hyp
sin80 = opp/12
opp = 12sin80
opp = 11.82 feet
Hence the height of the wall is 11.8feet (to the nearest tenth)
