All categories

3 years ago

Segment EF is a mid segment of triangle ABC. IF BC = 12 cm, what is the measure of segment EF?

Mathematics

2 answers:

Effectus [21]3 years ago

8 0

The answer is 6 cm. The mid segment is half of BC

Phoenix [80]3 years ago

4 0

Answer:

The measure of length of segment EF is 6 cm

C is correct.

Step-by-step explanation:

Segment EF is a mid segment of triangle ABC.

If BC = 12 cm

Please see the attachment for diagram.

EF is mid-segment of ABC

E is mid point of AB and F is mid point of AC.

Using mid point theorem.

EF is parallel to BC

EF is half of BC

$EF=\dfrac{1}{2}BC$

$BC=\dfrac{1}{2}\times 12 = 6$

Hence, The measure of length of segment EF is 6 cm

You might be interested in

A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?

DENIUS [597]

The answer is 15 in³.

The volume of the cone is:
$V_1= \pi r_1 ^{2} \frac{h_1}{3} = \frac{ \pi r_1^{2} h_1}{3}$
where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone

The volume of the cylinder is:
$V_2= \pi r_2h_2^{2}$
where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone

Since the cone fits exactly inside of the cylinder, they have the same radius and the height:
r₁ = r₂
h₁ = h₂

Also:
V₁ = 5

Now, let's write two volume formulas together:
$V_1= \frac{ \pi r^{2} h}{3}$
 $V_2= \pi rh^{2}$ 

We can include V₂ into V₁:
$V_1= \frac{V_2}{3}$

⇒ $V_2=3*V_1$
$V_2=3*5 in^{3}$
$V_2=15 in^{3}$

5 0

3 years ago

Hey ! Can anyone help me with this problem please thank you !!

Artist 52 [7]

Answer:

Step-by-step explanation:

7x + 3 = 8x + 1

2 = x

these are geometry problems.

3 0

3 years ago

It takes 54 minutes for 4 people to paint 6 walls. How many minuets does it take 6 people to paint 7 walls?

earnstyle [38]

It takes 42 minutes for 6 people to paint 7 walls

Solution:

It takes 54 minutes for 4 people to paint 6 walls

To find: Minutes required for 6 people to paint 7 walls

If $M_1$ men can do $W_1$ work in $D_1$ days working $H_1$ hours per day and $M_2$ men can do $W_2$ work in $D_2$ days working $H_2$ hours per day, then