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Paul [167]
3 years ago
13

Segment EF is a mid segment of triangle ABC. IF BC = 12 cm, what is the measure of segment EF?

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
The answer is 6 cm. The mid segment is half of BC
Phoenix [80]3 years ago
4 0

Answer:

The measure of length of segment EF is 6 cm

C is correct.

Step-by-step explanation:

Segment EF is a mid segment of triangle ABC.

If BC = 12 cm

Please see the attachment for diagram.

EF is mid-segment of ABC

E is mid point of AB and F is mid point of AC.

Using mid point theorem.

EF is parallel to BC

EF is half of BC

EF=\dfrac{1}{2}BC

BC=\dfrac{1}{2}\times 12 = 6

Hence, The measure of length of segment EF is 6 cm

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(i)
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8 0
3 years ago
Periodic Deposit: $7500 at the end of every six months
n200080 [17]

Answer:

The amount after 3 year at semi annually compound Interest is  $52186.203

Step-by-step explanation:

Given as

The amount deposit at the end of every six months  = $7500

Time period is 3 years ,

So principal for 3 years at $7500 for every six months = $7500 × 6 = $45,000

The rate of interest is 5% compounded semiannually

SO,  Amount = Principal (1 + \frac{Rate}{2 \times 100})^{2 \times time}

or,  Amount = $45,000 (1 + \frac{5}{2 \times 100})^{2 \times 3}

or,  Amount = $45,000 (1 + \frac{5}{200})^{6}

Or, Amount = $45,000×1.1596

So, Amount = $52186.203  

Hence The amount after 3 year at semi annually compound Interest is  $52186.203    Answer

3 0
4 years ago
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