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Ganezh [65]
3 years ago
9

Think about whether these ordered pairs represent a function. Then use the drop-down menus to complete the statement about the o

rdered pairs. (−2,4),(5,6),(0,1),(8,−7),(9,1)
this(does not/does)represents a function because different(x values/y values)can have the same (x values/y values) HELP MEH
Mathematics
2 answers:
dexar [7]3 years ago
8 0

Answer:

All x-coordinates are different, so this relation is a function.

Having the same y value more than once is not a problem for a function.

"This (does not/does) represents a function because different (x values/y values) can have the same (x values/y values)."

PIT_PIT [208]3 years ago
7 0

Answer:

1. does

2. x-values

3.y-values

Step-by-step explanation:

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What is the measure of the major arc?
ehidna [41]

Answer:

C. 225°.

Step-by-step explanation:

1) according to the condition minor arc is 135°;

2) the measure of the major arc can be calculated as

360°-135°=225°.

5 0
2 years ago
What kind of property is used in the following example?
aivan3 [116]
Commutative Property
7 0
3 years ago
A trapezoid has an area of 329 square feet. If the bases are 30 feet and 17 feet, what is the height of the trapezoid in feet? F
ExtremeBDS [4]

Answer:

The correct option is C.  14 ft

Step-by-step explanation:

To calculate the height, we will follow the steps below;

Formula is given to be:  h = 2A / b1 +b2

where h = height of the trapezoid   b1 and b2 are the bases of the trapezoid    and A is the area of the trapezoid

From the question given;

Area A =329 feet²      b1 = 30 feet    b2 =17 feet  

We can now proceed to insert the values into the formula

h = 2A / b1 +b2

h= 2(329)  / 30 + 17

h = 658 /47

h=14 feet

6 0
3 years ago
A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
Find the absolute value:<br> 5.34 -4 2/11 0<br> -6 3/5 -2.12 8.2
earnstyle [38]

Answer:

Change the positive numbers to negative and change the negative numbers to positive.

Step-by-step explanation:

I hope this helps u! :D

6 0
3 years ago
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