Answer:
Fred is 28 yrs old. Nathalie is 12yrs old
Step-by-step explanation:
Let Nathalie's age be x
Let Fred's age be a
x+a=40 yrs•••••1
4x+a=76yrs•••••2
a=40-x
Substitute a for 40-x in equation (2)
4x+40-x=76
3x=76-40
3x=36
x=12
a=40-12
a=28
The simplification form of the number expression (2⁴)⁻¹ is 1/2⁴ option (B) one over two raised to the fourth power is correct.
<h3>What is an integer exponent?</h3>
In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.
It is given that:
The number expression is:
= (2⁴)⁻¹
Using the properties of the integer exponent:
= 1/2⁴
The above number is one over two raised to the fourth power
Thus, the simplification form of the number expression (2⁴)⁻¹ is 1/2⁴ option (B) one over two raised to the fourth power is correct.
Learn more about the integer exponent here:
brainly.com/question/4533599
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the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
The formula for a cone is pi * r^2 * (h/3) or pi* r^2 * h * 1/3.
Since the height is 7ft and the radius if 4ft you plug those into the equation and get:
V= 1/3 * pi * (4^2) * (7)ft cubed which is the answer of B
Answer:
He have to eat each piece in 
Step-by-step explanation:
Given:
Brian claims that he can eat a pie that is divided into six equal pieces In two minutes.
If he can eat the whole pie in two minutes.
Now, to find the time he have to eat for each piece.
So, to solve by using unitary method:
If Brian can eat 6 pieces in = 2 minutes.
Then, he can eat 1 piece in = 
Therefore, he have to eat each piece in
