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astraxan [27]
3 years ago
15

What is the order of 75%, 1/3, 3/8, and 0.625 from least to greatest? Also, please please explain how to do it...I’m having trou

ble. Thanks!
Mathematics
2 answers:
tangare [24]3 years ago
5 0
3/8 , 1/3 , 75% , 0.625
Oksana_A [137]3 years ago
4 0

To arrange the given numbers from least to greatest we convert the numbers to decimal form.

75% =0.75

(Percent means out of 100.The decimal is shifted two places left to                               convert percent to decimal)

\frac{1}{3} =0.33

\frac{3}{8}=0.375

0.625

The  decimals from least to greatest are:

0.33,0.375,0.625,0.75.

The numbers arranged from least to greatest are:

\frac{1}{3},\frac{3}{8},0.625,75%

   

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Dimas [21]
X=2 because when you multiply 8 x 2=16 - 4=12
8(2)-4=12
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3 years ago
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Based on the graph, what is the solution set to 4x – 4 ≤ 4? (–∞, 5] (–∞, 4] (0, 4] [5, ∞)
Tomtit [17]

Answer:

It's A

Step-by-step explanation:

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3 0
3 years ago
Each day a small business owner sells 200 pizza slices at $3.00 per slice and 85 sandwiches at $2.50 each. Business expenses com
klio [65]

How much are the owner's expenses for 10 days?

10 * 130 = $1300

 

How much money does the owner make selling pizzas per day?

200 * 3 = $600

 

How much money does the owner make selling sandwiches per day?

85 * 2 = $170

 

In one day, the owner sells 600 + 170 = $770 worth of pizza and sandwiches

 

Over the course of ten days, that is 10 * 770 = $7700

 

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There ya go

5 0
3 years ago
Select the correct answer
jeka57 [31]
OB would be correct
6 0
4 years ago
Make v the subject of the formula in H=m(v²-u²)/2gx​
goldfiish [28.3K]

Answer:

v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Step-by-step explanation:

The given formula is :

H=\dfrac{m(v^2-u^2)}{2gx}

We need to find the formula for v.

Cross multiplying the given formula.

H\times 2gx=m(v^2-u^2)

Dividing both sides by m. So,

\dfrac{H\times 2gx}{m}=\dfrac{m(v^2-u^2)}{m}\\\\(v^2-u^2)=\dfrac{H\times 2gx}{m}

Adding both sides by u².

(v^2-u^2)+u^2=\dfrac{H\times 2gx}{m}+u^2\\\\v^2=\dfrac{H\times 2gx}{m}+u^2\\\\\text{So},\\\\v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Hence, this is the required formula.

4 0
3 years ago
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