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2 years ago

The question in the middle is it a b c or d ??

Mathematics

1 answer:

Artyom0805 [142]2 years ago

7 0

Yeah it’s a b c or d

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3 years ago

Write this as an equation, then solve.

ANTONII [103]

19.5 in difference
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3 years ago

If Peter withdrew $47.27 from the bank and deposited $598, how would his bank account change? (Indicate how much his account wou

fredd [130]

Answer:

Since we do not know the balance we should start with, a general answer:

$b_{new} = b_{old} + \sum_{i} d_{i} - \sum_{j} w_{j} \\$

598 - 47,27 = 550,73, assuming b_old was 0$ for your example

Step-by-step explanation:

b stands for balance (old - before any deposits or withdrawals, new after all done)

d for deposits

w for withdrawals

5 0

3 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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2 years ago

2 3/4÷2/5 will mark brainleyst

olga55 [171]

Answer:

6 7/8

Step-by-step explanation:

Result in decimals: 6.875

In pic

(Hope this helps can I pls have brainlist (crown) ☺️)

6 0

3 years ago

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