Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
192
i did that test before
Answer: 0,16,32,48,64
Step-by-step explanation: the equation 16b means you will multiple 16 by whatever is in the b box. For the first b is equal to 0 so 16x0 = 0, the second b is equal to 1 so 16x1 = 16
Answer: 378
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Work Shown:
f(x) = x^2 - 3x
f(x) = ( x )^2 - 3*( x )
f(-18) = ( -18 )^2 - 3*( -18 ) ... replace every x with -18; now use PEMDAS
f(-18) = 324 - 3*( -18 )
f(-18) = 324 + 54
f(-18) = 378
