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OlgaM077 [116]
3 years ago
13

Maya reads 1/8 of a newspaper in 1/28 of a minute.how many minutes does she need to read an entire paper

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
8/20 of a minute or 2/5 of a minute
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How many solutions does the nonlinear system of equations graphed below have?
saul85 [17]
Answer D zero there no solution
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2 years ago
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Solving Equations 3k+10=2k-21
Nikolay [14]

3k+10=2k-21

move 2k to the other side

sign changes from +2k to -2k

3k-2k+10=2k-2k-21( combine like terms)

3k-2k+10= -21

k+10=-21

move +10 to the other side

k+10-10= -21-10

k= -21-10

answer:

k= -31

6 0
3 years ago
I was taught how to do these I just don’t remember how to-3(4x+5)-2(-5x+8)
frosja888 [35]

Answer:

- 2x - 31

Step-by-step explanation:

Given

- 3(4x + 5) - 2(- 5x + 8)

Multiply the terms in the first parenthesis by - 3 and the terms in the second parenthesis by - 2

= - 12x - 15 + 10x - 16 ← collect like terms

= (- 12x + 10x) + (- 15 - 16)

= - 2x - 31

6 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
When using the vertical line test, if the vertical line hits the line in more than 1 place it is considered a function.
d1i1m1o1n [39]

Answer:

false

Step-by-step explanation:

If the vertical line hits more than 1 point it is not a function because the x value cannot repeat in order for it to be a function

4 0
2 years ago
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