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3 years ago

13

Maya reads 1/8 of a newspaper in 1/28 of a minute.how many minutes does she need to read an entire paper

1 answer:

zepelin [54]3 years ago

5 0

8/20 of a minute or 2/5 of a minute

You might be interested in

Which fraction is between 2/3 and 6/7

MrRa [10]

Answer:

For example, 16/21

Step-by-step explanation:

Are there choices?

There is an infinite number of numbers between any two numbers.

2/3 = 14/21

6/7 = 18/21

One example of a fraction between 2/3 and 6/7 is 16/21

16/21 is between 2/3 and 6/7.

5 0

2 years ago

For the feasibility region shown below, find the maximum value of the function P=2x+3y.

timofeeve [1]

Corner points in this graph are: ( 0,0 ) ( 0,8 ) ( 5,6 ) and ( 8, 0 ).
If we plug those values in : P = 2 x + 3 y
P ( 0,0 )= 0
P ( 0,8 ) = 2 * 0 + 3 * 8 = 24
P ( 6 , 5 ) = 2 * 6 + 3 * 5 = 12 + 15 = 27
P ( 8 , 0 ) = 2 * 8 + 3 * 0 = 16
The maximum value is:
P max ( 6 , 5 ) = 27

3 0

3 years ago

Read 2 more answers

x varies jointly with the square of y and z. when y=6 and z=5, x=100. Then, what is x when y=8 and z=2?

djyliett [7]

X = k*y^2 * z
100 = 6^2*5*k,
k=0.555
x=0.555zy^2

x=o.555(8^2)(2)=71.1112.

Hope that helps!

8 0

3 years ago

Three trucks delivered potatoes to a warehouse. The first truck delivered 5 7/8 tons of potatoes, the second one 6 1/2 tons more

mina [271]

Answer:

12 5/8 tons were delivered by the third truck

Step-by-step explanation:

25 = 6 4/8 + 5 7/8 + x

25 = 12 3/8 + x

- 12 3/8

12 5/8 = x

6 0

3 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago