Answer:
C. f has a relative maximum at x = 1.
Step-by-step explanation:
A. False. f(x) is concave down when f"(x) is negative. f"(x) is the tangent slope of the graph, f'(x). So f(x) is concave down between x = -1.5 and x = 1.5.
B. False. f(x) is decreasing when f'(x) is negative. So f(x) is decreasing in the intervals x < -3 and 1 < x < 2.
C. True. f(x) has a relative maximum where f'(x) = 0 and changes from + to -.
Answer:
If you want them at the same exact point then since the theif is 9 steps ahead it
will take 3 seconds
Step-by-step explanation:
Robber:
<em>starts at 9</em>
<em>starts at 9add on 5 and you get 14</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>
Police:
<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>
<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>
<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>
<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>
The solution to the equation is x < 1.25
With these transversals across parallel lines the angles are either congruent or supplementary (adding to 180) and its pretty easy to figure out which is which, obtuse verse acute in the figure.
Each yellow circle indicates x and the path to the next square. So for example the Start has alternate interior angles, which are congruent, so x is 141 degrees.
Answer:
Im either gonna say, the last one or the first. Please dont hate me.
