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ahrayia [7]
3 years ago
8

spontaneously form membranes when mixed in water and most likely were one of the first organic compounds formed on Earth?

Chemistry
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

phospholipids

Explanation:

As regards the lipid membrane of the first protocells, it is most likely that it initially consisted of simpler fatty acids than the phospholipids that make up the current membranes (see appendix). If the modern membranes are bilayers of glycerol phospholipids, the primitive membranes would probably be made up of simpler, single-chain molecules, also amphiphilic in nature (with a soluble part and another insoluble in water), such as monocarboxylic acids or alcohols. The origin of these compounds could be multiple. On the one hand, it has been seen that they are very abundant in meteorites of the type of carbonaceous chondrites, so they could have arrived on Earth already formed from outer space. But it is also possible that they were formed abioticly on the primitive Earth by the reaction of CO and hydrogen to give rise to various hydrocarbons, a reaction that would be viable at high temperatures in the presence of ferric catalysts, on the surface of montmorillonite clays and also in hydrothermal conditions. Regardless of the origin, the result would be the presence of fatty acids initially very diluted in an aqueous solution, but which would be concentrated by successive evaporation cycles, or by the formation of small aerosolized drops that would also transfer those vesicles to points distant from the place where The first organic membrane compounds that formed on Earth were formed and would be.

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When 1 mol of KBr(s) decomposes to its elements, 394 kJ of heat is absorbed. (a) Write a balanced thermochemical equation.
VladimirAG [237]

The balanced thermochemical equation is

KBr ------- K + 1/2 Br2

<h3>What is thermochemical equation? </h3>

A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.

The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :

KBr ----- K + Br2

The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows

KBr ------- K + 1/2 Br2

As the heat is absorbed in this reaction therefore, heat is positive.

Thus, we concluded that the balanced thermochemical equation is

KBr ------- K + 1/2 Br2

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8 0
2 years ago
Which of the following are considered pure substance??
Shkiper50 [21]

Answer:

Explanation:

I’m 99.9% sure that it’s an element because it can’t be broken down any more than it already is.

7 0
4 years ago
When a baseball bat hits a baseball, what happens to the energy?<br> completo ancur
professor190 [17]

Answer: the baseball bat transfor its energy in the ball.

Explanation: you hit it with one and find out and tell me what you think what happen.

3 0
3 years ago
2 HCl (g)
snow_tiger [21]

Yes. The model represents atoms rearranging to produce a new compound.

<h3>What chemical reactions?</h3>

They are reactions involving the breakage of bonds and rearrangement of atoms in reactants to form products.

In the model, the bonds between hydrogen and chlorine were broken. Thereafter, each hydrogen and chlorine molecule linked up to form hydrogen chloride.

Thus, the model shows atoms rearranging to produce a new compound.

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5 0
2 years ago
The speed of a spaceship is going warp 7.58. What is the velocity of the spaceship in cm/min. Assume 1.00 warp = 2.5 times the s
grandymaker [24]

Answer : The velocity of the spaceship is, 3408.6\times 10^{10}cm/min

Solution :

As we are given that,

1.00\text{ wrap }=2.5\times \text{The speed of light}

The speed of a spaceship = 7.58 wraps

So, 7.58\text{ wrap }=7.58\times 2.5\times \text{The speed of light}

The speed of light = 2.9979\times 10^8m/s

Now put the value of speed of light in above expression, we get

So, 7.58\text{ wrap }=(7.58)\times (2.5)\times (2.9979\times 10^8m/s)=56.81\times 10^8m/s

The velocity of the spaceship = 56.81\times 10^8m/s

Now we have to convert the velocity of the spaceship m/s to cm/min.

Conversion :

(1 m = 100 cm)

(1 min = 60 sec)

The velocity of the spaceship = (56.81\times 10^8)\times 100\times 60cm/min=3408.6\times 10^{10}cm/min

Therefore, the velocity of the spaceship is, 3408.6\times 10^{10}cm/min

3 0
3 years ago
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