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Marta_Voda [28]
3 years ago
14

All my questions are being "Deleted" for violating community guidelines by the same bots that scam you with the file. I swear- i

f it turns out the moderation team is scamming it's own site users.... (Not saying this is the case, but how does a scam 'bot' delete a question?)
Chemistry
1 answer:
Goryan [66]3 years ago
3 0

Answer:

well im not sure why

Explanation:

but this one isn't deleted yet sooo

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A buffer is prepared by adding 300. 0 ml of 2. 0 mnaoh to 500. 0 ml of 2. 0 mch3cooh. what is the ph of this buffer? ka= 1. 8 10
Anton [14]

The Henderson-Hasselbalch equation can be used to determine the pH of the buffer from the pKa value. The pH of the buffer will be 4.75.

<h3>What is the Henderson-Hasselbalch equation?</h3>

Henderson-Hasselbalch equation is used to determine the value of pH of the buffer with the help of the acid disassociation constant.

Given,

Acid disassociation constant (ka) = 1. 8 10⁻⁵

Concentration of NaOH = 2.0 M

Concentration of CH₃COOH = 2.0 M

pKa value is calculated as,

pKa = -log Ka

pKa = - log (1. 8 x 10⁻⁵)

Substituting the value of pKa in the Henderson-Hasselbalch equation as

pH = - log (1. 8 x 10⁻⁵) + log [2.0] ÷ [2.0]

pH = - log (1. 8 x 10⁻⁵) + log [1]

= 4.745 + 0

= 4.75

Therefore, 4.75 is the pH of the buffer.

Learn more about the Henderson-Hasselbalch equation here:

brainly.com/question/27751586

#SPJ4

6 0
2 years ago
Dimensional analysis, Plz hell I don’t understand and plz explain
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Explanation:

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7 0
3 years ago
Which ones are all renewable resources?
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D, they can be renewed quickly rather than non renewables in which nonrenewable take millions of years. Biomass is all around us, so is water (hydro) and the sun is around us too. 
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*Riddle!* *Riddle!!* *Riddle!!!*
otez555 [7]

Answer:

https://www.getriddles.com/science-riddles/

Explanation:

go to this link, you will find some answers

hope it helps!

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What is the concentration of a 500 mL solution with 25 mol of HF? Write your answer with TWO decimal places and round accordingl
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Answer:

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