All categories

3 years ago

A ridged steel tank filled with 62.7L of nitrogen gas of 85.0L atm

Chemistry

1 answer:

mylen [45]3 years ago

8 0

The final gas pressure : 175.53 atm

<h3>Further explanation</h3>

Maybe the complete question is like this :

A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?

The volume remains constant⇒Gay Lussac's Law

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature

$\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

P₁=85 atm

T₁=19+273=292 K

T₂=330+273=603 K

$\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm$

You might be interested in

Ethylene, a gas found in nature, is commonly used to ripen bananas and other fruits. Which compound is ethylene?

Reika [66]

Answer:

C2H4

Explanation:

cause the compound of ethylene is C2H4

6 0

3 years ago

Starting with 250 mL of a 0.250 M solution of HBr; a) Calculate the initial pH of the solution.b) Calculate the pH after adding

maxonik [38]

Answer:

pH = 0.602

pH = 1.5

pH = 7

pH = 12.1

Explanation:

a ) To calculate the pH, use the following equation:

pH = -log [H+]

Hbr is a strong acid, so the [H+] concentration can be calculated as follow:

[HBr] = 0.250 M

As acid Hbr:

Hbr = H+ + Br-

As strong acid HBr dissociates at all, so

[HBr] = [H+] = 0.250 M

So the pH:

pH = -log [0.250 M] = 0.602

b) Calculate the pH after adding 250 mL of 0.125M NaOH

In this point, the reactions starts:

HBr + NaOH = H2O + NaBr

- First, we gonna find the mol of each reactant:

HBr:

mol = [M] × L

mol = 0.250 M × 0.250 L

mol = 0.0625 mol HBr

NaOH:

mol = [M] × L

mol = 0.125 M × 0.250L

mol = 0.03125 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.03125 mol HBr = 0.03125 mol HBr

These are the moles free in the solution, and we going to use them to calculate the pH:

pH = -log [ H]

pH = - log [ 0.03125 ] = 1.5

c) Calculate the pH after adding 500 mL of 0.125M NaOH

NaOH:

mol = [M] × L

mol = 0.125 M × 0.500L

mol = 0.0625 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.0625 mol HBr = 0 HBr

pH = 7

d) Calculate the pH after adding 600 mL of 0.125M NaOH.

NaOH:

mol = [M] × L

mol = 0.125 M × 0.600L

mol = 0.075 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.075 mol NaOH – 0.0625 mol NaOH = 00125 NaOH

These are the moles free in the solution, and we going to use them to calculate the pH:

pOH = -log [ OH]

pOH = - log [ 0.0125 ] = 1.90

pH + pOH = 14

pH = 14- pOH = 14 – 1.90 = 12.1

4 0

3 years ago

Which of the following changes on different celestial objects due to the force of gravity?

marshall27 [118]

Weight
Everything else stays the same. Weight is determined by how much you are being pulled down by gravity

3 0

3 years ago

Sodium electron configuration unabbreviated

Tema [17]

Answer: [Ne] 3s¹

Explanation:

6 0

3 years ago

A lead atom has a mass of 3.14 x 10 to the negative 22nd g.How

frozen [14]

Explanation:

The given data is as follows.

Mass of a lead atom = $3.14 \times 10^{-22}$

Volume = 2.00 $cm^{3}$

Density = 11.3 $g/cm^{3}$

As it is mentioned that 1 cubic centimeter contains 11.3 grams of lead.

So, in 2 cubic centimeter there will be $2 \times 11.3 g = 22.6 g$ of lead atoms.

One lead atom has a mass of $3.14 \times 10^{-22}$ . Therefore, number of atoms present in 22.6 g of lead will be as follows.

$\frac{22.6 g}{3.14 \times 10^{-22}}$

= $7.197 \times 10^{22} atoms$

Thus, we can conclude that there are $7.197 \times 10^{22} atoms$ of lead are present.

4 0

3 years ago