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2 years ago

A ridged steel tank filled with 62.7L of nitrogen gas of 85.0L atm

Chemistry

1 answer:

mylen [45]2 years ago

8 0

The final gas pressure : 175.53 atm

<h3>Further explanation</h3>

Maybe the complete question is like this :

A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?

The volume remains constant⇒Gay Lussac's Law

<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature </em>

$\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

P₁=85 atm

T₁=19+273=292 K

T₂=330+273=603 K

$\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm$

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3 years ago

The balanced equation for water is 2 H2 + O2 to 2 H2O. If I have 21.2g of a product , and I started with 5.6 g of H2, how many g

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3 years ago

The atom with the same number of neutrons as 12C is 9Be. 11B. 13C. 14N.

julia-pushkina [17]

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Now we have to determine the number of neutrons in the given options.

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Number of neutrons = Atomic mass number - Atomic number = 11 - 5 = 6

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Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 13 - 6 = 7

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Atomic mass number = 14

Atomic number = 7

Atomic number = Number of protons = Number of electrons = 7

Number of neutrons = Atomic mass number - Atomic number = 14 - 7 = 7

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