Answer:
r - 5 = 2c
r = 75
Step-by-step explanation:
To write an equation for the problem, we first need do declare the value of the number of apps cora has.
Let c = Cora's apps
r - 5 = 2c
r - 5 is used to indicate that Rita deleted 5 apps.
2c is used to represent the twice the number of apps Cora has.
Now you said that Cora had 35 apps.
Let's plug that into the equation.
r - 5 = 2c
r - 5 = 2(35)
r - 5 = 70
Now we transpose the -5 to the other side to leave r.
r = 70 + 5
r = 75
So if Cora has 35 apps, then Rita will have 75 apps.
sqrt (5x - 9) - 1 = x
sqrt(5x - 9) = x + 1
Square both sides:_
5x - 9 = x^2 + 2x + 1
x^2 - 3x + 10 = 0
(x - 5)(x + 2) = 0
x = 5 or -2.
Lets look for for any extraneous solutions:-
x = 5 ; sqrt (5*5-9) - 1 = sqrt16 - 1 = 3 and x = 3 (right hand side of equation)
so x = 5 is a solution
x = -2: sqrt(5*-2 - 9) - 1 = sqrt (-19) - 1 and x = -2 so this is extraneous
Answer:- One solution x = 5
Simplifying
2x + 3y = 12
Solving
2x + 3y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3y' to each side of the equation.
2x + 3y + -3y = 12 + -3y
Combine like terms: 3y + -3y = 0
2x + 0 = 12 + -3y
2x = 12 + -3y
Divide each side by '2'.
x = 6 + -1.5y
Simplifying
x = 6 + -1.5y