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3 years ago

Can you please help with this math?>>

Mathematics

2 answers:

goblinko [34]3 years ago

6 0

x = 16 x sin(60) = 8sqrt(3)

answer is B.

lana66690 [7]3 years ago

6 0

16 is your hypotenuse, (2)
The top length is your (1)
The x is your (√3)

To find x, first find your side 1, by dividing the side "2" number by half
16/2 = 8

Than place the 8 with the √3

8√3 is your answer

hope this helps

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Which ordered pairs are in the solution set of the system of linear inequalities?

Elanso [62]

Answer:

The ordered pairs (5 , -2) , (3 , 1) , (4 , 2) are in the set of the solution ⇒

3rd answer

Step-by-step explanation:

- The first line has negative slope and passing through points (0 , 0)

and (4 , -2)

∵ $y>\frac{-1}{2}x$

- The second line has positive slope and passing through points (-2 , 0)

and (2 , 2)

∵ $y$

- Look to the attached figure to see the common part of the solutions

- The red shaded represents the inequality $y>\frac{-1}{2}x$

- The blue shaded represents the inequality $y$

- The shaded part with two colors represents the common solutions

of the two inequalities

- Lets find the ordered pairs which are in the solution set of the system

of linear inequalities

- Points (-4 , 2) , (-3 , 1) , (4 , -3) lies out the common shaded

- Points (5 , -2) , (3 , 1) , (3 , -1) , (4 , 2)

∵ Point (5 , -2) lies in the common shaded part

∵ Point (3 , 1) lies in the common shaded part

∵ Point (4 , 2) lies in the common shaded part

∴ The ordered pairs (5 , -2) , (3 , 1) , (4 , 2) are in the set of the

solution

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4 years ago

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Which set of ordered pairs does NOT show y as a function of x?

Vladimir79 [104]

Answer:

Your answer would be (B. I don't know what the options are, but I did a quiz with this question, and picked B. And got a %100!

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3 years ago

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Suppose the six people consist of three mar- ried couples and each couple wants to sit together with the older partner on the le

chubhunter [2.5K]

6 possible ways to order 3 couples in a row

Given,

We have three married couples. that is six persons in total.

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Considering the statement:

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Then we have, (a, b) ------ ( 1)

(c, d) ------ (2)

(e, f) ------ (3)

There is no change in position between the couples.

So, we get three persons in total.

Possible ways to order these three persons will be like this: 3! = 3×2×1

= 6

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2 years ago

7. The following values were measured at 1- metre intervals. Plot and apply simple 3-point and 5-point filters. What are the max

san4es73 [151]

Answer:

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4 years ago

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'

aleksandr82 [10.1K]

Answer:

A. △P'Q'R' does not equal △P''Q''R''.

B. Reflecting across UT would change the orientation of the figure.

C. The sequence does not include a reflection that exchanges U and S.

D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.

E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.

(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]

Step-by-step explanation:

Proof No.1

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

Proof No.2

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

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3 years ago