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lorasvet [3.4K]
4 years ago
15

A plane contains at least how many points that are on the same line

Mathematics
1 answer:
UNO [17]4 years ago
5 0
A plane contains infinite points!

Unless there are restrictions, of course. (ex: x ≤ 0)

Hope this helps!

You might be interested in
3x + 2y = 6 what is x and y
uysha [10]

Answer:

For 3x + 2y = 6 , the x-intercept is 2 and the y-intercept is 3.

4 0
3 years ago
Read 2 more answers
2. A palindrome is a number or a word that is the same in the two directions: left to right and vice
a_sh-v [17]

Answer:

90 between 1000 and 9999

Step-by-step explanation:

The first digit cannot be 0. It can be nine other digits.

The second digit can be anything between 0 and 9.

To be palindromic the 2nd and 3rd digits must be the same.

And in addition, the 1st and 4 numbers must be the same.

So the answer is 9 * 10 = 90. That does seem too small, but try making a palindrome with the restrictions I have outlined. None of the examples you have given beginning with 8 are palindromic.

8118 is palindromic

8998 is also palindromic

9009 is palindromic

2002 is palindromic

There are only 90 of them.

6 0
3 years ago
If 124 is subtracted from the square of a number the result is 200 what is the number​
omeli [17]

Answer:

Step-by-step explanation:

let the number =x

then

x²-124=200

x²=200+124

x²=324

x=18

4 0
3 years ago
Simplify the expression completely.<br> -3V24 - V.
Maru [420]

Answer:

-V (3 V^23 + 1)

Step-by-step explanation:

Simplify the following:

-3 V^24 - V

Factor -V out of -3 V^24 - V:

Answer:  -V (3 V^23 + 1)

5 0
4 years ago
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
Tatiana [17]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
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