Question

-3/7, -8/3 and -5/2,-2 slope

Answer 1

So the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2

subsitute
$\frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} }$
simplify by finding similar denomenators
$\frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} }$
$\frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} }$
add
$\frac{\frac{2}{3}}{ \frac{-29}{14}}$
multiply top and bottom by $\frac{-14}{29$
$\frac{\frac{-28}{87}}{1}$
$\frac{-28}{87}$
answer is
slope=$\frac{-28}{87}$