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lbvjy [14]
3 years ago
11

Please help me with this assignment I need help and been struggling with it so please help me and is due by 7;50 pm please answe

r 5-8

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

5. DBE and CBA both=48 degrees

6. a. scalene, right

b.isosceles, obtuse

c. scalene, acute

7. 50 degrees

8. im not completely sure how to do this one but ill check into it

Step-by-step explanation:

its a lot to explain, in 5 find p and plug it in.

in 6, just look at the sides and angles.

scalene- no sides equal

isosceles- 2 sides equal

equilateral- all sides equal

right- one 90 degree angle

acute- all acute angles (less than 90)

obtuse- one obtuse angle (more than 90)

7. add 90 and 40 to get 130. 180-130=50

8. im gonna look up how to do this one right now

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8 0
3 years ago
Y/4+−49=−9
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4 0
3 years ago
Read 2 more answers
The variables xx and yy vary directly. use the values to find the constant of proportionality, kk. then write an equation that r
Sergeu [11.5K]
Direct variation means that changes in x will result to changes in y. If x increase, y also increases and vice versa.

y = kx
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y = 45 ; x = 40

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5 0
3 years ago
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Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
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