This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
If that 25/4 is a fraction them the answer is 53/4. Or in simplest form 3 5/16 or 3.3125
why do u cheat in exams lol
To solve this problem you must apply the proccedure shown below:
1. When you plot the given points, you obtain a trapezoid, therefore, you must apply the formula for calculate the area of a trapezoid, which is:
Where 
is the larger base, 
is the smaller base and 
is the height.
2. The dimensions are:
3. Substitute values:
The answer is: 
Answer:
Step-by-step explanation:
Let the rate of boat in still water be b and the speed of the current be c
- Speed downstream = b + c
- Speed upstream = b - c
<u>We got equations for time:</u>
- 108/(b - c) = 3 ⇒ b - c = 36
- 108/(b + c) = 2 ⇒ b + c = 54
<u>Add up the equations:</u>
- b - c + b + c = 36 + 54
- 2b = 90
- b = 45 km/h
<u>Then finding the values of c</u>
