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My name is Ann [436]
3 years ago
12

How to find slope of parall lines

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0
Y=mx+b
M= slope of parallel line
I hope that helped
Lostsunrise [7]3 years ago
7 0
Search it up on the internet
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Given f(x)=4x^3-3x^2+10 use the remainder theorem to find f(-2)
ozzi
To do this, you would need to use synthetic division.

-2 | 4 -3 10
-8 22
4 -11 32

Your reminder would be 32.

Sorry if my graph of synthetic division is a bit messy, you can only do so much on a phone!
8 0
4 years ago
WILL MARK BRAINLIEST IF CORRECT❤️❤️<br> Simplify the expression -5+i/2i<br> Step by step
zhenek [66]

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

5 0
3 years ago
Read 2 more answers
The measure of angle A is 15°, and the length of side
dangina [55]

Answer:

Part 1) AB=30.9\ units

Part 2) AC=29.9\ units

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

sin(A)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(15^o)=\frac{8}{AB}

solve for AB

AB=\frac{8}{sin(15^o)}=30.9\ units

Part 2

Find the length side AC

we know that

tan(A)=\frac{BC}{AC} ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

tan(15^o)=\frac{8}{AC}

solve for AC

AC=\frac{8}{tan(15^o)}=29.9\ units

8 0
3 years ago
Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9
AnnZ [28]

Answer:

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

Step-by-step explanation:

We have been given that

f(x)=x^3-27,g(x)=3x-9

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes -  a^3-b^3=(a-b)(a^2+ab+b^2)

f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)

And g(x) can be written as

g(x)=3x-9\\=3(x-3)

Thus, we have

(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}

On cancelling the common factors, we get

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

5 0
3 years ago
Exercise 7.8.29. [S] Flying twice as far.
dalvyx [7]
Hey z shs d 2 , e dndbdjdbdud us ske ux he 4 670.2
3 0
3 years ago
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