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eduard
3 years ago
15

If you are given the lengths of two sides of a right triangle and do not know the angle measures of any angle besides the right

angle, the way to find the third side length of the triangle is by using the Pythagorean theorem. Question 4 options:
True

False
Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0
True
The pythagorean theorem only needs two sides of a right triangle
grin007 [14]3 years ago
8 0
I have to write twenty characters but the answer is TRUE!
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Is (2, 5) a solution to this system of inequalities?<br><br> 4x + 2y &gt; 18<br> 13x + y ≤ 7
Alborosie

Answer: 4x + 2y > 18 (not sure though)

Step-by-step explanation:

5 0
3 years ago
Please help me with this literal equation!
ollegr [7]

Answer:

x = \frac{n-20}{3a}

Step-by-step explanation:

Given

\frac{3ax-n}{5} = - 4

Multiply both sides by 5

3ax - n = - 20 ( add n to both sides )

3ax = - 20 + n = n - 20

Isolate x by dividing both sides by 3a

x = \frac{n-20}{3a}

4 0
3 years ago
Read 2 more answers
Find an input that yield an output of -1 rule y=-2x+33
djyliett [7]

Input (x-value)

Output (y-value)

You need to find the x-value that produces a y-value of -1. Since you know:

y = -1       Use the rule, and substitute/plug this into the equation

y = -2x + 33       Plug in -1 for "y" in the equation since y = -1

-1 = -2x + 33        Subtract 33 on both sides

-1 - 33 = -2x + 33 - 33

-34 = -2x      Divide -2 on both sides to get "x" by itself

\frac{-34}{-2}=\frac{-2x}{-2}

17 = x

An input of 17 yields an output of -1

3 0
3 years ago
Exercise 30 please , show work
ArbitrLikvidat [17]
-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\&#10;=-16a+24b-30b+20a= \\&#10;=20a-16a+24b-30b= \\&#10;=(20-16)a+(24-30)b= \\&#10;=4a-6b
3 0
3 years ago
Read 2 more answers
Please help! I'm super confused.
stich3 [128]

<u>Answer:</u>

10y + 2

<u>Step-by-step explanation:</u>

The formula for the perimeter of a rectangle or square is [length + length + width + width = perimeter  or  2(length) + 2(width) = perimeter]

Our length here is y + 2. Either formula you use, [(y+2) + (y+2) or 2(y+2)] you should get the answer 2y + 4.

Next our width. The width is 4y-1. Either formula you use, [(4y-1) + (4y-1) or 2(4y-1)] you should get 8y - 2.

Then, simply add (2y+4) and (8y-2) to get 10y + 2. So, the perimeter of the garden is 10y + 2.

I hope this helps!

5 0
3 years ago
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