We have events:
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:
![P(A)=0.69\\\\P(B)=0.46\\\\P(A\cap B)=0.36](https://tex.z-dn.net/?f=P%28A%29%3D0.69%5C%5C%5C%5CP%28B%29%3D0.46%5C%5C%5C%5CP%28A%5Ccap%20B%29%3D0.36)
so:
![P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.69+0.46-0.36=\boxed{0.79}](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3DP%28A%29%2BP%28B%29-P%28A%5Ccap%20B%29%3D0.69%2B0.46-0.36%3D%5Cboxed%7B0.79%7D)
</span>
Answer:
baby, I don't know
Step-by-step explanation:
Answer:
1190
Step-by-step explanation:
Amount of walnuts=![\frac{3}{4} kg](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20kg)
Amount of almonds=![\frac{1}{2} kg](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20kg)
Amount of pecans=![\frac{1}{4} kg](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20kg)
Total amount=![\frac{3}{4}+\frac{1}{2}+\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%2B%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B4%7D)
LCM is 4 so sum is =
=![\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D)
As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:
![\frac{\frac{3}{2}}{\frac{3}{10}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B3%7D%7B2%7D%7D%7B%5Cfrac%7B3%7D%7B10%7D%7D)
=
= 5
Hence, answer is 5 bags.
what do you mean ¨ what is the distance between¨ what is the rest of the question?