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777dan777 [17]
3 years ago
12

Write the equation of the line in slope-intercept from the graph below.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0
The answer: y=3/2x-2
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Please go to this link and answer my question the last person is being an idiot and didn't answer and kept telling me to click l
garik1379 [7]

You're not allowed to put links in the question.

8 0
3 years ago
X+y-z=5 -x-4y-8z=6 3x+5y-4z=-20
Juli2301 [7.4K]

Answer:

x = 24.48, y = -15.52, z = 3.95 to the nearest hundredth.

Step-by-step explanation:

 x+y-z=5             (a)

-x-4y-8z=6          (b)

3x+5y-4z=-20      (c)

Adding equations a and b:

-3y - 9z = 11       (d)

Now multiply equation b by 3:

-3x - 12y - 24z = 18        (e)

Adding  c and e:

-7y - 28z = -2      (f)  Multiply by 3 to give (g)

-3y - 9z = 11         (b)   Multiply by  -7 to give (h)

-21y - 84z = -6     (g)

21y + 63z = -77    (h)    Adding g and h:

-21z = - 83

z =  3.952

and y is found bt substituting in equation d:

-3y - 9(3.952) = 11

y = ( 11 + 9(3.952) / -3

= -15.52.

Now find x by substituting for y an z in equation a:

x - 15.52 - 3.952 = 5

x = 5 + 15.52 + 3.952

= 24.476.

3 0
3 years ago
Express the following linear equations in the form ax+by+c= 0 and indicate the values of a, b and c in each case: (1) y = x/5​
EleoNora [17]

Answer:

Did the question get cut off?

a = -(1/5)

b = 1

c = 0

Step-by-step explanation:

y = x/5 may be rewritten as y = (1/5)x

y = (1/5)x

y - (1/5)x = 0

- (1/5)x + y + 0 = 0

   ax  +   by   + c = 0

a = -(1/5)

b = 1

c = 0

8 0
2 years ago
A number added to 3 is equal to negative 5, find the number​
anzhelika [568]

Answer:

-8

Step-by-step explanation:

An equation at represents this situation is:

-5 = 3 + x

Find x by;

-5 - 3 = -8

So x is -8:

-5 = 3 + -8 (TRUE)

Hope this helps

6 0
3 years ago
Read 2 more answers
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
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