Answer:
x = 24.48, y = -15.52, z = 3.95 to the nearest hundredth.
Step-by-step explanation:
x+y-z=5 (a)
-x-4y-8z=6 (b)
3x+5y-4z=-20 (c)
Adding equations a and b:
-3y - 9z = 11 (d)
Now multiply equation b by 3:
-3x - 12y - 24z = 18 (e)
Adding c and e:
-7y - 28z = -2 (f) Multiply by 3 to give (g)
-3y - 9z = 11 (b) Multiply by -7 to give (h)
-21y - 84z = -6 (g)
21y + 63z = -77 (h) Adding g and h:
-21z = - 83
z = 3.952
and y is found bt substituting in equation d:
-3y - 9(3.952) = 11
y = ( 11 + 9(3.952) / -3
= -15.52.
Now find x by substituting for y an z in equation a:
x - 15.52 - 3.952 = 5
x = 5 + 15.52 + 3.952
= 24.476.
Answer:
Did the question get cut off?
a = -(1/5)
b = 1
c = 0
Step-by-step explanation:
y = x/5 may be rewritten as y = (1/5)x
y = (1/5)x
y - (1/5)x = 0
- (1/5)x + y + 0 = 0
ax + by + c = 0
a = -(1/5)
b = 1
c = 0
Answer:
-8
Step-by-step explanation:
An equation at represents this situation is:
-5 = 3 + x
Find x by;
-5 - 3 = -8
So x is -8:
-5 = 3 + -8 (TRUE)
Hope this helps
Answer:
At 43.2°.
Step-by-step explanation:
To find the angle we need to use the following equation:
Where:
d: is the separation of the grating
m: is the order of the maximum
λ: is the wavelength
θ: is the angle
At the first-order maximum (m=1) at 20.0 degrees we have:
Now, to produce a second-order maximum (m=2) the angle must be:
Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.
I hope it helps you!
