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3 years ago

At what point do the graphs of the equation 9x-2y=30 and x+2y=10 intersect?

Mathematics

1 answer:

iren [92.7K]3 years ago

3 0

X + 4.5y = 20 is the answer

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Help with #9 pleaseeee

Molodets [167]

Answer:

9' - 1.29"

Step-by-step explanation:

Total rise = 5' - 2"

Total run = 7' - 6"

1' = 12" = 1 feet = 12 inches

5' = 5 * 12 = 60"

3' = 7 * 12 = 84"

Total rise = 60" + 72" = 62"

Total run = 84" + 6" = 90"

Length of stringer = hypotenus

Hypotenus = √(total rise² + total run²)

Hypotenus = √(62² + 90²)

Hypotenus = 109.28860"

Convwrting back to feet and inches

= 9' - 1.29"

3 0

3 years ago

PLZ HELPPP OMG I WILL GIVE 50 POINTS NOT A SCAM I HAVE A QUIZ GRADE DEPENDS ON THIS

nekit [7.7K]

Answer:

Step-by-step explanation:

All I know is x is 20 and y is $48.75 sorry.

5 0

3 years ago

What is the value of x?

LiRa [457]

Answer:

98°

Step-by-step explanation:

x = 53° + 45° { exterior angle of a triangle is equal to the sum of two opposite interior angles }

x = 98°

5 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago

If 6x = 1/126 find the value<br> of x.

Anastasy [175]

Answer:

x = $\frac{1}{756}$

Step-by-step explanation:

Given

6x = $\frac{1}{126}$ ( divide both sides by 6 )

x = $\frac{\frac{1}{126} }{6}$ = $\frac{1}{126}$ × $\frac{1}{6}$ = $\frac{1}{126(6)}$ = $\frac{1}{756}$

6 0

3 years ago

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