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Crank
3 years ago
11

Javier’s movie collection consists of 3 action movies, 5 comedies, and 9 dramas. In a rush, he randomly grabs 3 movies to bring

on a plane flight. What is the probability that he chose 2 action movies and 1 comedy?
Mathematics
2 answers:
Furkat [3]3 years ago
7 0

Answer:

3/136 is the simplified answer I believe

jasenka [17]3 years ago
5 0
The required probability is found as follows:
P(2\ action+1\ comedy)=\frac{3C2\times5C1}{17C3}=\frac{3\times5}{680}=\frac{1}{136}\ or\ 0.022
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Answer:375

Step-by-step explanation:

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3 years ago
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Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Which is the correct factoring of
Igoryamba

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C. (X+2)(x-6)

Step-by-step explanation:

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3 years ago
Help me ill give u a thanks!
stiv31 [10]

Answer:

11. 68.6 mph

12. 5/6 page (0.83)

Step-by-step explanation:

You simply divide them (remember the word "per" means divide).

\dfrac{120}{1 \frac34} \approx 68.6

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