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Jet001 [13]
3 years ago
5

Triangle G H F is shown. Angle F G H is a right angle. The length of G H is 28 and the length of hypotenuse F H is 40.

Mathematics
2 answers:
kolbaska11 [484]3 years ago
5 0

Answer:

44.4

Step-by-step explanation:

right on edge

neonofarm [45]3 years ago
3 0
Using the sine rule:

40/sin(90) = 28/sin(x)

These are two fractions that are equal so we can cross multiply to get:

40 x sin(x) = 28 x sin(90)

Rearranging:

sin(x) = (28 x sin(90))/40

Take inverse sine to find x (the angle)

x = sin^-1(28 x sin(90))/40)

X = 44.4° to 1dp

Lmk if anything’s unclear.
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Answer:

See below.

Step-by-step explanation:

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= 8/27.

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Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. A(1,0), B(3,6), C(-1,4)
Karo-lina-s [1.5K]

Answer:

45°, 45°, 90°

Step-by-step explanation:

Find the vectors to represent each sides

AB =<3-1, 6-0>=<2,6>  

AC = < -1-1, 4 - 0 > = < -2, 4>

Magnitude of the vectors

AB = √(2²+6²) = 6.32

AC = √ ((-2)² + 4²) = 4.47

cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504

θ = arcos(20 / 28.2504 ) approx = 45°

Magnitude of the vectors

BA =<1-3,0-6>=<-2,-6>

BC =<-1-3,4-6>=<-4,-2>

Magnitude of the vectors equals

BA = √((-2)² + (-6)²) = 6.325

BC = √((-4)² + (-2)²) = 4.4721

cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286

θ  = arcos (20 / 28.286 ) = 45°

Magnitude of the vectors

CB =<3--1, 6-4>=<4,2>

CA=<1--1,0-4>=<2,-4>

Magnitude of the vector =

CB = √(4² + 2²) = 4.4721

CA = √(2² + (-4)²) = 4.4721

cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0

θ = arcos 0 = 90°

4 0
3 years ago
Can I please have help, I don't know how to solve this.<br><br> 3741 = P(P-1) over 2
STatiana [176]

Answer:

The values of P are -87 or 86.

Step-by-step explanation:

Given:

3741=\frac{P(P-1)}{2}

Multiply by 2 on both the sides. This gives,

3741\times 2=\frac{P(P-1)}{2}\times 2\\7482=P(P-1)

Now, use distribution property.

7482=P\times P - P\times 1\7482=P^2-P

Now, add -7482 on both sides,

P^2-P-7482=0

This is a quadratic equation of the form ax^2+bx+c=0 which can be solved using quadratic formula with a=1,b=-1,c=-7482

P=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\P=\frac{-1\pm\sqrt{(-1)^2-4(1)(-7482)}}{2(1)}\\P=\frac{-1\pm\sqrt{1+29928}}{2}\\P=\frac{-1\pm\sqrt{29929}}{2}\\P=\frac{-1-173}{2}\textrm{ or }P=\frac{-1+173}{2}\\P=\frac{-174}{2}\textrm{ or }P=\frac{172}{2}\\P=-87\textrm{ or }P=86

Therefore, the values of P are -87 or 86

6 0
3 years ago
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