we are given point as
(x,y)=(5,7)
translating 3 units to right side
It means we will subtract 3 to x-value
and we get
(x,y)= (5-3,7)
(x,y)=(2,7)
now, it is reflected about x-axis
so, we can change y-value as -y
so, we get our new point as
(x,y)=(2,-7)
now, we have to find it's image reflection
so, we will get
(x',y')=(-7,2).........Answer
Answer:
21
Step-by-step explanation:
7.41 / 0.13 = 57
57 - 15 = 42
42 / 2 = 21
21, 36
Part A
See the image labeled "part A". We'll use the values marked in blue and red for f(2) and g(2) respectively. These values are the function outputs when the input is x = 2.
(f-2g)(x) = f(x) - 2*g(x)
(f-2g)(2) = f(2) - 2*g(2)
(f-2g)(2) = 1 - 2*3
(f-2g)(2) = -5
Answer: -5
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Part B
See the image labeled "part B". We'll use the values marked in blue and red for g(-1) and f(0) respectively.
We have to start with g(-1) and then chain it to finding f(0) afterward.
g(-1) = 0
f(g(-1)) = f(0) = 9
Answer: 9
=====================================================
Part C
See the image labeled "part C". We'll use the values marked in blue and red for g(-2) and g(-3) respectively.
Because g(-2) is the innermost function, it must go first, then g(-3) can go next.
g(-2) = -3
g(g(-2)) = g(-3) = 8
Answer: 8
That would be week 2 and 4 (B). They are both at 12 students attending
Hope this helped!
A
The answer is a trust me