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Evgen [1.6K]
3 years ago
11

chad wants to buy some books over the internet. each book costs $10.01 and has a shipping cost of $9.96 per order. if chad wants

to spend no more than $50 for his books, which inequality shows the maximum number of books, p, that he can buy? 9.96p − 10.01p ≤ 50, so p ≤ 1 9.96p 10.01p ≤ 50, so p ≤ 2 9.96 − 10.01p ≤ 50, so p ≤ 3 9.96 10.01p ≤ 50, so p ≤ 4
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

If you would like to find the inequality that shows the maximum number of books that he can buy, you can do this using the following steps:

p ... number of books

$10.01 * p + $9.96 <= $50

10.01 * p + 9.96 <= 50

10.01 * p <= 50 - 9.96

10.01 * p <= 40.04

p <= 40.04 / 10.01

p <= 4 books

Read more on Brainly.com - brainly.com/question/1629451#readmore

Step-by-step explanation:

Serga [27]3 years ago
3 0
If you would like to find the inequality that shows the maximum number of books that he can buy, you can do this using the following steps:

p ... number of books

$10.01 * p + $9.96 <= $50
10.01 * p + 9.96 <= 50
10.01 * p <= 50 - 9.96
10.01 * p <= 40.04
p <= 40.04 / 10.01
p <= 4 books

The correct result would be <span>9.96 + 10.01p ≤ 50, so p ≤ 4.</span>
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On the last three physics exams a student scored 89, 87, and 92. What score must the student earn on the next exam to have an av
OlgaM077 [116]

Answer:

For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

Step-by-step explanation:

The score of students in last 3 exams =  89 , 87 and 92

Let us assume the marks scored by the student in last exam = k

The average of marks should be above 90.

Now, \textrm{The average of total marks}  = \frac{\textrm{Sum of all marks obtained in 4 papers}}{\textrm{ 4 papers }}

Sum of all 4 paper's marks =  89 + 87 + 92 + k = 268 + k

Also, 90 <  Average

\implies 90 < \frac{268 + k}{4}\\ or, 360 < 268 + k\\\implies  360 - 268 < k\\or,  k >  92

Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

4 0
3 years ago
An ancient Chinese candle clock tells the amount of time that has passed by the amount of wax that has been melted off the candl
maxonik [38]

Answer:

Time = 560\ mins

Step-by-step explanation:

Given

Candles = 2 --- candles melted

Divisions = 12

Time = 4\ hrs --- time to melt

Required

The time since the first was lit

If 1 candle melts in 4 hours, 2 candles will melt in 8 hours.

i.e.

x = Candles * Time

x = 2 * 4hrs

x = 8hrs

For the 3rd candle that has melted, 4 inches

First, calculate the fraction that melt

Fraction = \frac{Melt}{Division}

Fraction = \frac{4}{12}

Fraction = \frac{1}{3}

The time to melt is:

y = Fraction * Time

y= 4 * \frac{1}{3}

y= \frac{4}{3}hrs

So, the required time is:

Time = x + y

Time = 8hrs + \frac{4}{3}hrs

Convert to minutes

Time = 8*60mins + \frac{4}{3}*60mins

Time = 480mins + 80mins

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4 0
2 years ago
If a football is thrown upward, its height above the
dybincka [34]

Answer:

a) s = -16t^{2} + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16t^{2} + V_{o}t + s_{o}

where: s is the height of the football above the ground, t is the time, V_{o} is the initial velocity and s_{o} is the initial height.

The height of the building = V_{o} = 192 feet and the initial speed of the ball = s_{o} = 96 feet per second, then;

s = -16t^{2} + 192t + 96

a) The polynomial is given as:

s = -16t^{2} + 192t + 96

b) The height of the football when t = 2 seconds is;

s = -16(2) + 192(2) + 96

 = -32 + 384 + 96

 = -32 + 480

s = 448

The height of the football when t = 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

7 0
2 years ago
On which attempts was his time less than 60 seconds?
adelina 88 [10]

Answer:

4 6 and 7?

Step-by-step explanation:

all you have to do is find 60 sec mark and all attempts bellow it are below 60 sec or under 60 sec

5 0
2 years ago
2.5 divided by 23.35
joja [24]
10.7=11 is the answer to 23.5 divide by 2.5
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3 years ago
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