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3 years ago

What multiples into 4 and adds up to 5

Mathematics

2 answers:

vampirchik [111]3 years ago

6 0

Answer:

4 and 1

4 * 1 = 4

4 + 1 = 5

crimeas [40]3 years ago

5 0

Answer:

(2x+1) (x+2)

Step-by-step explanation:

2x^2 +5x+2

(2x + ) (x+ )

We need to determine what goes in the empty spots

2 factors into 2 and 1 so we have two options

(2x + ) (x+ ) the first spot can be either 2 or 1 and the second spot can be the other

We need to get to 5 so I will put the 2 where it will multiply by the 2x

(2x+1) (x+2)

Check

FOIL

2x^2 +4x +x+2

2x^2 +5x+2

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Ghella [55]

$10-\frac{3x-1}{2} =\frac{6x+3}{11}$

$10 = \frac{6x+3}{11} + \frac{3x-1}{2}$

$10 = (\frac{6x+3}{11} \times \frac{2}{2} ) + (\frac{3x-1}{2} \times \frac{11}{11} )$

$10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )$

$10 = \frac{12x + 6}{22} + \frac{33x - 11}{22}$

$10 = \frac{12x + 6 + 33x - 11}{22}$

$10 = \frac{(12 x + 33x) + (6 - 11)}{22}$

$10 = \frac{45x - 5}{22}$

$10 \times 22 = 45x - 5$

$220 = 45x - 5$

$220 + 5 = 45x$

$225 = 45x$

$\frac{225}{45} = x$

$\frac{45}{9} = x$

$5 = x$

7 0

1 year ago

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the

Sergio [31]

Answer: The maximum profit that can make by the company is $461. x= Number of widget. The profit of the company will maximum only when if they sell widget.

3 0

2 years ago

Work out the mean for the data set below: 6, 4

aliina [53]

Answer:

Step-by-step explanation:

The mean is the same as the average value of a data set and is found using a calculation. Add up all of the numbers and divide by the number of numbers in the data set.

8 0

3 years ago

What is the sum of the complex numbers 6+5i and 8+3i2? (NOTE: −1‾‾‾√=i )

Ahat [919]

Answer:

11 + 5i

Step-by-step explanation:

6 + 5i + 8 + 3i² =

= 6 + 8 + 3(-1) + 5i

= 14 - 3 + 5i

= 11 + 5i

4 0

2 years ago

Question 12<br> With steps please

34kurt

$Answer:\ \boxed{5^2}$

$\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}$

6 0

3 years ago